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zhannawk [14.2K]
3 years ago
15

Triangle ABC has vertices at A(−3, 4), B(4, −2), C(8, 3). The triangle is translated 4 units down and 3 units left. Which rule r

epresents the translation? After the translation, what are the coordinates of vertex C?
Mathematics
2 answers:
mylen [45]3 years ago
8 0

Answer:

(x,y) ⇒ (x - 3) (y - 4)

C(5, -1)

Step-by-step explanation:

mel-nik [20]3 years ago
4 0

Answer:

C) (x, y) → ( x − 3, y − 4); (5, −1)

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If a polynomial function f(x) has roots 1+square root of 2 and-3, what must be a factor of f(x)?
nevsk [136]
To find the factor a a polynomial from its roots, we are going to seat each one of the roots equal tox, and then we are going to factor backwards.

We know for our problem that one of the roots of our polynomial is -3, so lets set -3 equal tox and factor backwards:
x=-3
x+3=0
(x+3) is a factor of our polynomial.

We also know that another root of our polynomial is 1+ \sqrt{2}, so lets set 1+ \sqrt{2} equal to x and factor backwards:
x=1+ \sqrt{2}
x-1= \sqrt{2}
x-1- \sqrt{2}=0
(x-(1+ \sqrt{2})=0
((x-(1+ \sqrt{2} )) is a factor of our polynomial.

We can conclude that there is no correct answer in your given choices.
8 0
3 years ago
Jolly Middle School is building a park, in the shape of a square, with an area of 256 square feet. How much fence do they need t
kumpel [21]

Answer:

well that would mean that the perimeter is 256/4 and that is 64

Step-by-step explanation:

i think the answer is 64

6 0
3 years ago
Read 2 more answers
The time for this event for boys in secondary school is known to possess a normal distribution with a mean of 460 seconds and a
AlekseyPX

Answer:

The time that the boys need to beat in order to earn a certificate of recognition from the fitness association is 511.264 seconds.

Step-by-step explanation:

We are given that the time for this event for boys in secondary school is known to possess a normal distribution with a mean of 460 seconds and a standard deviation of 40 seconds.

The fitness association wants to recognize the fastest 10% of the boys with certificates of recognition.

<u><em>Let X = time for this event for boys in secondary school</em></u>

SO, X ~ Normal(\mu=460,\sigma^{2} =40^{2})

The z-score probability distribution for normal distribution is given by;

                               Z = \frac{X-\mu}{\sigma} ~ N(0,1)

where, \mu = mean time = 460 seconds

            \sigma = standard deviation = 40 seconds

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

<u>Now, it is given that the fitness association wants to recognize the fastest 10% of the boys with certificates of recognition, which means;</u>

       P(X > x) = 0.10   {where x is the required time which boy need to beat}

       P( \frac{X-\mu}{\sigma} > \frac{x-460}{40} ) = 0.10

        P(Z > \frac{x-460}{40} ) = 0.10

<em>So, the critical value of x in the z table which represents the top 10% of the area is given as 1.2816, that is;</em>

<em>                   </em>      \frac{x-460}{40} =1.2816

                         {x-460}{} =1.2816\times 40

<em>                           </em>x = 460 + 51.264 = <u>511.264 seconds</u>

Hence, the time that the boys need to beat in order to earn a certificate of recognition from the fitness association is 511.264 seconds.

8 0
3 years ago
Please help and work out both questions! ill give brainlest and 20 points
raketka [301]

Answer:

Step-by-step explanation:

6. Use PEMDAS

-3 x (7 + (-3)*2) / 3

-3 x (7 + 9) / 3

-3 x 16 / 3

-48 / 3

-16

7. 9 (x) = -63

X = - 63 /9

X = -7

6 0
3 years ago
Read 2 more answers
What are the fourth roots of 6+6√(3i) ?
Helen [10]

Answer:

Step-by-step explanation:

The genral form of a complex number in rectangular plane is expressed as z = x+iy

In polar coordinate, z =rcos ∅+irsin∅ where;

r is the modulus = √x²+y²

∅ is teh argument = arctan y/x

Given thr complex number z = 6+6√(3)i

r = √6²+(6√3)²

r = √36+108

r = √144

r = 12

∅ = arctan 6√3/6

∅ = arctan √3

∅ = 60°

In polar form, z = 12(cos60°+isin60°)

z = 12(cosπ/3+isinπ/3)

To get the fourth root of the equation, we will use the de moivres theorem; zⁿ = rⁿ(cosn∅+isinn∅)

z^1/4  = 12^1/4(cosπ/12+isinπ/12)

When n = 1;

z1 =  12^1/4(cosπ/3+isinn/3)

z1 = 12^1/4cis(π/3)

when n = 2;

z2 = 12^1/4(cos2π/3+isin2π/3)

z2 = 12^1/4cis(2π/3)

when n = 3;

z2 = 12^1/4(cosπ+isinπ)

z2 = 12^1/4cis(π)

when n = 4;

z2 = 12^1/4(cos4π/3+isin4π/3)

z2 = 12^1/4cis(4π/3)

8 0
3 years ago
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