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BaLLatris [955]
3 years ago
12

If the perimeter of a square is 36 cm, what is the area?

Mathematics
1 answer:
Evgesh-ka [11]3 years ago
4 0
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He answered 41 questions right.

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100 points + brainlest please help due today
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Use the formula for direct variation

Step-by-step explanation:

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Which of the following is most likely to bra relative maximum for this graph?
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(-1,8)

Step-by-step explanation:

Look at the top point of the parabola type thing. I know that it's not a parabola, but IDRK how else to describe it. If you see the top point at one of the answers, it is most likely correct.

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3 years ago
1,2,5,10,17 What is the pattern
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Going up by odd numbers I’m pretty sure

Step-by-step explanation:

1-2 that went up once

2-5 that went up 3 times

5-10 that went up 5

and so on

6 0
3 years ago
A raffle offers a first prize of $1000, 2 second prizes of $300, and 20 third prizes of $10 each. If 20000 tickets are sold at 2
Shalnov [3]

Answer:

The expected winnings for a person buying 1 ticket is -0.2.                  

Step-by-step explanation:

Given : A raffle offers a first prize of $1000, 2 second prizes of $300, and 20 third prizes of $10 each. If 20000 tickets are sold at 25 cents each, find the expected winnings for a person buying 1 ticket.

To find : What are the expected winnings?    

Solution :

There are one first prize, 2 second prize and 20 third prizes.

Probability of getting first prize is \frac{1}{20000}

Probability of getting second prize is \frac{2}{20000}

Probability of getting third prize is \frac{20}{20000}

A raffle offers a first prize of $1000, 2 second prizes of $300, and 20 third prizes of $10 each.

So, The value of prizes is

\frac{1}{20000}\times 1000+\frac{2}{20000}\times 300+\frac{20}{20000}\times 10

If 20000 tickets are sold at 25 cents each i.e. $0.25.

Remaining tickets = 20000-1-2-20=19977

Probability of getting remaining tickets is \frac{19977}{20000}

The expected value is

E=\frac{1}{20000}\times 1000+\frac{2}{20000}\times 300+\frac{20}{20000}\times 10-\frac{19977}{20000}\times 0.25

E=\frac{1000+600+200-4994.25}{20000}

E=\frac{-3194.25}{20000}

E=-0.159

Therefore, The expected winnings for a person buying 1 ticket is -0.2.

3 0
3 years ago
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