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shtirl [24]
3 years ago
11

Step by step to how to solve quadratic equation given the roots ​

Mathematics
1 answer:
Triss [41]3 years ago
3 0

 

\displaystyle\it\\\text{We have the equation: }\\\\ax^2+bx+c=0\\\\\text{We find the roots:}\\\\x_{12}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x_{1}=\frac{-b+\sqrt{b^2-4ac}}{2a}\\\\x_{2}=\frac{-b-\sqrt{b^2-4ac}}{2a}\\\\\text{If } b^2-4ac>0 \text{ then }x_1, x_2\in~R\\\\\text{If } b^2-4ac=0 \text{ then }x_1=x_2\in~R\\\\\text{If } b^2-4ac

.

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4 5/6+3/5= my daughter is needing help she's in the 5th grade
V125BC [204]

Answer:5 13/30

Step-by-step explanation:

4+5/6 + 3/5

5/6 +3/5

Find LCD of 5/6 and 3/5

25/30 + 18/30

43/30= 1 13/30

4+1+13/30= 5 13/30

7 0
3 years ago
Read 2 more answers
Simplify (5^3 x 5^5)^5 A. 5^13 B. 5^20 C. 5^75 D. 5^40
Anarel [89]
When you multiply powers inside the parenthesis, you add them.

3+5=8

(5^8)^5

When powers are outside the parenthesis, you multiply them.

5*8= 50

5^40

Remember: you keep the constant the same. (5)

“D” is the answer.

I hope this helps!
~kaikers

7 0
3 years ago
(3a2 + 2ab + 2b) + (5a2 − 3ab + 9)
ivann1987 [24]

Step-by-step explanation:

\tt{(3 {a}^{2}  + 2ab + 2b) + (5 {a}^{2}  - 3ab + 9})

~While adding , the sign of each term of second expression remains same. So, Remove the unnecessary parentheses :

⤑ \tt{3 {a}^{2}  + 2ab + 2b + 5 {a}^{2}  - 3ab + 9}

~Like terms are those which have the same base. Combine the like terms :

⤑ \tt{3 {a}^{2}  + 5 {a}^{2}  + 2ab - 3ab + 2b + 9}

⤑ \sf{8 {a}^{2}  - ab + 2b + 9}

\red{ \boxed{ \boxed{ \tt{ ⟿ Our \: final \: answer : 8 {a}^{2}  - ab + 2b + 9}}}}

Hope I helped ! ツ

Have a wonderful day / night ♡

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6 0
3 years ago
Read 2 more answers
Perpendicular and Angle bisectors​
olchik [2.2K]
I remember this but I dead forgot how to do it
8 0
3 years ago
What is the value for x?
schepotkina [342]
Right of the bat, I know the measure of angle C equals 73° because of the Isosceles Base Angle Theorem. Then, due to the Triangle Sum Theorem, I know that all of the measures in the triangle must add to 180°. To find this, just subtract 73 and 73 from 180. Finally, because angle B equals (6x + 4) and 34°, just set them equal to each other to find the value of x.


180 - 73 - 73 = measure of angle B
34° = measure of angle B

6x + 4 = 34
      - 4    - 4
6x = 30
6x / 6 = 30 / 6
x = 5

Hope this helps!
3 0
3 years ago
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