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shtirl [24]
3 years ago
11

Step by step to how to solve quadratic equation given the roots ​

Mathematics
1 answer:
Triss [41]3 years ago
3 0

 

\displaystyle\it\\\text{We have the equation: }\\\\ax^2+bx+c=0\\\\\text{We find the roots:}\\\\x_{12}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x_{1}=\frac{-b+\sqrt{b^2-4ac}}{2a}\\\\x_{2}=\frac{-b-\sqrt{b^2-4ac}}{2a}\\\\\text{If } b^2-4ac>0 \text{ then }x_1, x_2\in~R\\\\\text{If } b^2-4ac=0 \text{ then }x_1=x_2\in~R\\\\\text{If } b^2-4ac

.

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Can u guys answer this quick question plssss WILL GIVE BRAINLIEST
Vlad1618 [11]

Answer: -2x - 4

Step-by-step explanation: This is because it has a variable in it, making it an algebraic expression.

4 0
3 years ago
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3 years ago
What point approxmiates the square root of 10
Juli2301 [7.4K]

Answer:

Calculate the square root of 10 ( ) to 2 decimal places.

Find the two perfect square numbers it lies between. Solution: 32 = 9 and 42 = 16, so lies between 3 and 4.

Divide 10 by 3. 10/3 = 3.33 (you can round off your answer)

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Step-by-step explanation:

7 0
2 years ago
Simplify:<br><br><br>4(r + 1) + 3r<br><br> A. 4r + 4<br> B. 5r + 1<br> C. 7r + 1<br> D. 7r + 4
klasskru [66]

Answer:

look in the explanation, it is in there

Step-by-step explanation:

i don't know if you are distributing or just using PEMDAS .

if you are distributing then: do in the equation 4(r + 1) + 3r.. do 4 x r and 4 x 1 , now you have 4r + 4 + 3r

                        7r +4

                      is what i got!

If you are doing PEMDAS then: first you do what is inside the perenthisis ()

4(r + 1) +3r changes into

4( r1 ) + 3r now you do multipulcation because that in the "M" in pemdas

4r + 3r, then if you are using like terms you would add them

7r

i hope this helps you out!

6 0
3 years ago
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Valentin [98]

Answer:

x is 122

Step-by-step explanation:

7 0
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