Question

Find the value of x and y given that p//q. Type answers alphabetically, and separate by a comma and a space

Answer 1

As angle 6y° and angle( 13y - 10 )° are interior angles on the same side of transversal their sum will be equal to 180° .

Then :-

$6y + 13y - 10 = 180$

$19y - 10 = 180$

$19y = 180 + 10$

$19y = 190$

$y = \frac{190}{19}$

$y = 10$

Which means :-

= 13y - 10

= 13 × 10 - 10

= 130 - 10

= 120°

Then angle 6y :-

= 6 × 10

= 60°

As angle 60° and angle 9x + 12° are a linear their sum will also add up to form 180° .

Which can be written as :-

$60 + 9x + 12 = 180$

$9x + 72 = 180$

$9x = 180 - 72$

$9x = 108$

$x = \frac{108}{9}$

$x = 12$

Then :-

= Angle 9x + 12

= 9 × 12 + 12

= 108 + 12

= 120°

Therefore , the value of y = 10 and the value of x = 12 .