<h3>Jason bought 20 stamps of $0.41 each and 8 postcards of $0.26 each.</h3>
<em><u>Solution:</u></em>
Let stamps be s and postcards be p
Given that,
The number of stamps was 4 more than twice the number of postcards
s = 4 + 2p -------- eqn 1
Jason bought both 41-cent stamps and 26-cent postcards and spent $10.28
41 cent = $ 0.41
26 cent = $ 0.26
Therefore,

0.41s + 0.26p = 10.28 --------- eqn 2
Substitute eqn 1 in eqn 2
0.41(4 + 2p) + 0.26p = 10.28
1.64 + 0.82p + 0.26p = 10.28
1.08p = 10.28 - 1.64
1.08p = 8.64
Divide both sides by 1.08
p = 8
Substitute p = 8 in eqn 1
s = 4 + 2(8)
s = 4 + 16
s = 20
Thus Jason bought 20 stamps and 8 post cards
Answer:
2
Step-by-step explanation:
i used a calculator and the rounded
When it hits the ground the height would be 0.
Set h to 0 and solve for t ( time)
0 = -16t^2 + 112t + 144 divide both sides by -16:
T^2 -7t -9
Factor the polynomial :
( t- 8.1) (t+1.1
Solve for t setting each equation to 0:
T = 8.1 or t = -1.1
Time has to be positive, so the answer is
8.1 seconds
Depending on how everything gets rounded it could also be 8 seconds.
Answer:
De value of k is 9
Step-by-step explanation:
6,-1
b(1,3)
(k,8)
am using bodmas
a6-1×1=6a
b1×3=3b
abc=8
6a+3b+8=17-8
=9