Answer:
73 nickels, 27 dimes
Step-by-step explanation:
x+y=100
5x+10y=635
x=100-y
5(100-y)+10y=635
500-5y+10y=635
500+5y=635
5y=135
y=27
5x+10(27)=635
5x+270=635
5x=365
73
73+27=100
The sum of all the even integers between 99 and 301 is 20200
To find the sum of even integers between 99 and 301, we will use the arithmetic progressions(AP). The even numbers can be considered as an AP with common difference 2.
In this case, the first even integer will be 100 and the last even integer will be 300.
nth term of the AP = first term + (n-1) x common difference
⇒ 300 = 100 + (n-1) x 2
Therefore, n = (200 + 2 )/2 = 101
That is, there are 101 even integers between 99 and 301.
Sum of the 'n' terms in an AP = n/2 ( first term + last term)
= 101/2 (300+100)
= 20200
Thus sum of all the even integers between 99 and 301 = 20200
Learn more about arithmetic progressions at brainly.com/question/24592110
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Answer:
oh! thanks for points
but this is yr question or what????
300/min
300/60 seconds
300 divided by 60=5
5 ft/second
5ft=60 inches
60 inches/second
Final Answer: B
The right answer for the question that is being asked and shown above is that: ""I'll probably try it, but only if I have a discount coupon." = 153 responses." The relative error is <span>"I'll probably try it, but only if I have a discount coupon." = 153 responses</span>
