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zheka24 [161]
3 years ago
5

Will give BRAINLIEST

Mathematics
2 answers:
neonofarm [45]3 years ago
6 0

Step-by-step explanation:

f(x) = 2x + 1. Let y = f(x).

Then y = 2x + 1, 2x = y - 1, x = (y - 1)/2.

If h(x) is the inverse of f(x), then h(x) = (x - 1)/2 = 0.5x - 0.5.

expeople1 [14]3 years ago
3 0
I believe it’s C but I could be wrong I’m sorry, is this precalc?
You might be interested in
Evaluate 64 1\2 * 10(-2) as a fraction
melamori03 [73]

Answer:

1/25

Step-by-step explanation:

64^=8

8*1/2=8/2

10^-2=1/100

8/2*1/100

1/25

This is picture for more preference.

8 0
3 years ago
I will give brainiest but plzz help fast
Lena [83]

Answer:

Hi there!

The correct answer to this question is: The <u>surface area</u> of the prism is 456 cm^2. The <u>volume</u> of the prism is 408 cm^2

8 0
4 years ago
Estimate the minimum and maximum ages for typical textbooks currently used in college courses, then use the range rule of thumb
Maksim231197 [3]

Answer:

n=(\frac{1.64(4)}{0.25})^2 =688.537 \approx 689

So the answer for this case would be n=689 rounded up to the nearest integer

Step-by-step explanation:

Assuming this complete question: "Suppose that the minimum and maximum ages for typical textbooks currently used in college courses are 0 and 8 years. Use the range rule of thumb to estimate the standard deviation.

Estimate the minimum and maximum ages for typical textbooks currently used in college courses, then use the range rule of thumb to estimate the standard deviation. Next, find the size of the sample required to estimate the mean age (in years) of textbooks currently used in college courses. Use a 90% confidence level and assume that the sample mean will be in error by no more than 0.25 year."

Solution for the problem

First we need ti find the estimation for the standard deviation using the Rule of thumb, with the following formula:

s \approx \frac{R}{4}

Where R is the range defined as :

R = Max - Min = 8-0 = 8

So then the deviation would be approximately:

s \approx 4

Important concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error (ME) is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The margin of error is given by this formula:

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}    (1)

And on this case we have that ME =\pm 0.25 and we are interested in order to find the value of n, if we solve n from equation (1) we got:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2   (2)

We can assume that the estimator for the population deviation from the rule of thumb is \hat \sigma = s= 4

The critical value for 90% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.05;0;1)", and we got z_{\alpha/2}=1.64, replacing into formula (2) we got:

n=(\frac{1.64(4)}{0.25})^2 =688.537 \approx 689

So the answer for this case would be n=689 rounded up to the nearest integer

6 0
3 years ago
The graphs of ​ f(x)=−5/3x+9 ​ and ​ g(x)=2^x−1​ intersect at (3, 4) .
Vinil7 [7]
If they intersect at this point, that means this point is a solution (3,4)
3 0
3 years ago
The population of a certain species of insect is given by a differentiable function P , where P(t) is the number of insects in t
Dmitriy789 [7]

Answer:

Option C, dP/dt=1/5P

Step-by-step explanation:

The change is population of insects is directly proportional to the rate of change of population

Hence,

\frac{dP}{dt} \alpha P

Or \frac{dP}{dt} = kP

where K is the proportional constant

We will find the value of k

Keeping the given values of rate of change of population and population in above equation, we get -

\frac{2}{10} = k\\k = \frac{1}{5}

Hence,

\frac{dP}{dt} = \frac{1}{5} P

3 0
3 years ago
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