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3 years ago

PLEASE, I AM DESPERATE! CAN ANYONE, HELP ME WITH MY MATH!

1 answer:

5 0

(6,1)&(5,4)
(7,-3)&(4,-8)
(-8,0)&(1,5)
Basically, you are to find the line that passes through 2 points.
Equation: y2-y1=m(x2-x1)
• x1: 6, x2: 5, y1: 1, y2: 4
(4-1)/(5-6)=m
m=3/-1
m=-3
Hence, m= -3x10^0

• x1: 7, x2: 4, y1: -3, y2: -8
(-8--3)/(4-7)=m
m=(-8+3)/-3
m=-5/-3
m=5/3
m=1.66666667
Hence, m=1.6667x10^0

• x1: -8, x2: 1, y1: 0, y2: 5
(5-0)/(1--8)=m
m=5/(1+8)
m=5/9
m=0.55555556
Hence, m=5.56x10^-1

Hope this helps!

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Lelechka [254]

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3 years ago

Read 2 more answers

A bee flies at 9 feet per second directly to a flower bed from its hive. The bee stays at the flowerbed for 15 minutes, and then

Ivan

Complete question is;

A bee flies at 9 feet per second directly to a flower bed from its hive. The bee stays at the flowerbed for 15 minutes, and then flies directly back to the hive at 6 feet per second. It is away from the hive for a total of 18 minutes.

a. What equation can you use to find the distance of the flowerbed from the hive?

b. How far is the flowerbed from the hive?

Answer:

A) (d/9) + 900 + (d/6) = 1080

B) d = 648 ft

Step-by-step explanation:

A) We are told that A bee flies at 9 feet per second directly to a flower bed from its hive.

Time taken is given as;

t = distance/speed

If distance is d from the hive to the flower bird.

Then, t1 = d/9

The bee stays at the flowerbed for 15 minutes. Thus, time spent at the flowerbird in seconds is; t2 = 15 × 60 = 900 seconds.

We are told that the bee flew directly back to the hive at 6 feet per second.

Thus,time is;

t3 = d/6

Since total time spent away from hive is 18 minutes, then converting to seconds, we have; t = 18 × 60 = 1080 s

Thus;

(d/9) + 900 + (d/6) = 1080

B) Since we have derived;

(d/9) + 900 + (d/6) = 1080

Then we can find d.

Multiply through by 18 to get;

2d + (900 × 18) + 3d = 1080 × 18

2d + 16200 + 3d = 19440

5d = 19440 - 16200

5d = 3240

d = 3240/5

d = 648 ft

4 0

3 years ago

A certain car model has a mean gas mileage of 34 miles per gallon (mpg) with a standard deviation A pizza delivery company buys

zubka84 [21]

Answer:

$z =\frac{33.3- 34}{\frac{5}{\sqrt{54}}}= -1.028$

$z =\frac{34.3- 34}{\frac{5}{\sqrt{54}}}= 0.441$

An we can use the normal standard table and the following difference and we got this result:

$P(-1.028$

Step-by-step explanation:

Assuming this statement to complete the problem "with a standard deviation 5 mpg"

We have the following info given:

$\mu = 34$ represent the mean

$\sigma= 5$ represent the deviation

We have a sample size of n = 54 and we want to find this probability:

$P(33.3 < \bar X< 34.3)$

And for this case since the sample size is large enough >30 we can apply the central limit theorem and then we can use this distribution:

$\bar X \sim N(\mu , \frac{\sigma}{\sqrt{n}})$

And we can use the z score formula given by:

$z=\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And replacing we got:

$z =\frac{33.3- 34}{\frac{5}{\sqrt{54}}}= -1.028$

$z =\frac{34.3- 34}{\frac{5}{\sqrt{54}}}= 0.441$

An we can use the normal standard table and the following difference and we got this result:

$P(-1.028$

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3 years ago

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ivolga24 [154]

Answer:

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Step-by-step explanation:

I attached a file.

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3 years ago

The two intervals (114.9, 115.7) and (114.6, 116.0) are confidence intervals (computed using the same sample data) for μ = true

kenny6666 [7]

Answer:

115.3 hertz

Step-by-step explanation:

For either interval, the value of the sample mean is given by the average of the lower and upper bound of the confidence interval. Since both intervals were constructed by using the same sample, both values should be equal.

For the first interval:

$M=\frac{114.9 + 115.7}{2} \\M=115.3\ hertz$

For the second interval:

$M=\frac{114.6 + 116.0}{2} \\M=115.3\ hertz$

4 0

3 years ago