Question

Plsss need help ans this or the before one​

Answer 1

Answer:

  1

Step-by-step explanation:

Use the form for the factoring of the sum of cubes.

To make this easier to write, we'll use the substitutions ...

  a = sin(θ), b = cos(θ)

It looks like you may want to simplify ...

  (a³ +b³)/(a +b) +ab

  = ((a +b)(a² -ab +b²))/(a +b) +ab

The factors of (a+b) cancel. In this case, we know that a² +b² = 1, so this becomes ...

  = (1 -ab) +ab

  = 1

  $\boxed{\dfrac{\sin^3{\theta}+\cos^3{\theta}}{\sin{\theta}+\cos{\theta}}+\sin{\theta}\cos{\theta}=1}$