Plsss need help ans this or the before one

Mathematics

1 answer:

DedPeter [7]3 years ago

3 0

Answer:

Step-by-step explanation:

Use the form for the factoring of the sum of cubes.

To make this easier to write, we'll use the substitutions ...

a = sin(θ), b = cos(θ)

It looks like you may want to simplify ...

(a³ +b³)/(a +b) +ab

= ((a +b)(a² -ab +b²))/(a +b) +ab

The factors of (a+b) cancel. In this case, we know that a² +b² = 1, so this becomes ...

= (1 -ab) +ab

= 1

$\boxed{\dfrac{\sin^3{\theta}+\cos^3{\theta}}{\sin{\theta}+\cos{\theta}}+\sin{\theta}\cos{\theta}=1}$

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EXPRESSION:-

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<h3>ANSWER-></h3>

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