Question

Find two consecutive numbers if the square root of the smaller number is 3 less than the bigger number.

Answer 1

Answer:

The numbers are 4 and 5

Step-by-step explanation:

Let

x------> the smaller number

x+1----> the bigger number

we know that

$\sqrt{x}=(x+1)-3$ ----> equation that represent the situation

solve for x

$\sqrt{x}=(x-2)$

squared both sides

$x=(x-2)^{2}\\x=x^{2}-4x+4\\x^{2}-5x+4=0$

using a graphing calculator to solve the quadratic equation

see the attached figure

the solution is

$x=4$

$x+1=5$