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3 years ago

How do you solve a diagonal?

1 answer:

7 0

Assuming you mean the diagonal of a rectangle, the diagonal is basically the pythagorean theorem, where the diagonal is c and where a and be are the length and width.

a²+b²=c²

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Divide 4x^3 + 2x^2 + 3x + 4 by x + 4

Archy [21]

It would be -232
I hope this helps!!
If you need me to explain it i will.

5 0

3 years ago

Read 2 more answers

You can use a system of equations to graph and solve the polynomial equation 3x^3 + x = 2x^2 +1 which statement is true?

Anna35 [415]

Answer:

The y-coordinates of the solutions to the system and the zeroes of the equation are not equal.

Step-by-step explanation:

7 0

4 years ago

Which of these is a complex number? <br><br> A. <br><br> B. <br><br> C. <br><br> D.

Step2247 [10]

Answer:

option D

$\frac{8}{3} + \sqrt{\frac{-7}{3} }$

Step-by-step explanation:

Given in the question are 4 number

5√1/3 - $\frac{9}{\sqrt{7} }$

2 - $\frac{1}{\sqrt{11} }$

9 + $3\sqrt{\frac{5}{2} }$

$\frac{8}{3} + \sqrt{\frac{-7}{3} }$

A Complex Number is a combination of a Real Number and an Imaginary Number

<h3>Example </h3>

a + ib

where a is real number

b is imaginary number

i is 'lota' which is √-1

<h3>So according to the definition above </h3>

$\frac{8}{3} + \sqrt{\frac{-7}{3} }$ is complex number in which

$\frac{8}{3}$ is real part

$\sqrt{\frac{7}{3} } \sqrt{-1}$ = $\sqrt{\frac{7}{3} } i$ is the imaginary part

7 0

4 years ago

Solve for variable y answer in simplest radical form

ASHA 777 [7]

Answer:

option A

Step-by-step explanation:

option A y = 9√3 is the correct answer .

In∆ PQR

cos 30 = y /18

√3/2 = y / 18

y = 9√ 3

plz mark my answer as brainlist plzzzz.

hope this will be helpful to you .

4 0

3 years ago

I WILL GIVE BRAINLIEST PLEASE HELP (picture)

Blizzard [7]

$0.\overline{7}=0.777...\\\\x=0.777...\qquad\text{multiply both sides by 10}\\\\10x=7.777...\\\\\text{Make the difference}\\\\10x-x=7.777...-0.777...\\\\9x=7\qquad\text{divide both sides by 9}\\\\x=\dfrac{7}{9}\\\\Answer:\ \boxed{0.\overline{7}=\dfrac{7}{9}}\\-----------------\\You\ can\ remember\\\\\dfrac{1}{9}=0.\overline{1}\\\\\dfrac{2}{9}=0.\overline{2}\\\\\dfrac{3}{9}=0.\overline{3}\\\\\dfrac{4}{9}=0.\overline{4}\\\vdots\\\\\dfrac{8}{9}=0.\overline{8}$

8 0

3 years ago