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siniylev [52]
3 years ago
13

The sum of two integers is 54 and the difference is 10. Fin the integers

Mathematics
1 answer:
Setler [38]3 years ago
4 0

Answer:x + y = 54

x - y = 10

Add them to get: 2x = 64

x = 32

and plugging in x = 32 to either equation: y = 22

Ans: the numbers are 22 and 32

Step-by-step explanation:

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10=c+d<br> c is one more than d <br> what is the value of c?<br>with working out
Leya [2.2K]
C= 5.5 I'm pretty sure that's the answer

d= 4.5 and c+ 5.5
Because 4.5 plus 1.0 = 5.5
since c is one more than d

5.5 plus 4.5 = 10
5 0
3 years ago
Help me w the answer
Olin [163]
I have no clue. im on that same question
3 0
3 years ago
What is the solution for x in the equation?<br> -2x+14+10x=34
NemiM [27]

Answer: The solution of x is 2.5

Step-by-step explanation: hope it helps:)

5 0
1 year ago
Read 2 more answers
Help on 3. And 4. Thank you!
chubhunter [2.5K]

Answer:

#3.) The initial value of  16 gal at  x = 5 minutes means that 16 gallons of water was present 5 minutes after the barrel started leaking.

#4.) Find how many minutes until the barrel is empty of water.

Let y = 0,  to solve for time x.

0 = (-2/5)*x + 18

(2/5)*x = 18

x = (5/2)* 18 = 5*9 = 45 minutes

Up to and after 45 minutes, the barrel is empty of water.

Step-by-step explanation:

#2.)  

minutes:      5, 10, 15, 20

water(gal):  16, 14, 12, 10

Find slope:    slope m = (14 - 16)/(10 - 5) = -2/5

y - 10 = (-2/5)*(x - 20)

y - 10 = (-2/5)* x  + 8

y = (-2/5)*x + 18

rate of change slope means that for every minute  2/5 gallons of water is lost

#3.) The initial value of  16 gal at  x = 5 minutes means that 16 gallons of water was present 5 minutes after the barrel started leaking.

#4.) Find how many minutes until the barrel is empty of water.

Let y = 0,  to solve for time x.

0 = (-2/5)*x + 18

(2/5)*x = 18

x = (5/2)* 18 = 5*9 = 45 minutes

4 0
3 years ago
2<br> (<br> 3<br> r<br> +<br> 4<br> )<br> −<br> 3<br> (<br> r<br> +<br> 1<br> )<br> =<br> 11
Slav-nsk [51]

Answer:

Kindly rewrite the question clearly.

8 0
2 years ago
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