Minimum : 0
maximum: 12
first quartile: 1
median: 2
third quartile: 4
Answer:
The equivalent will be:
![\frac{\sqrt[7]{x^2}}{\sqrt[5]{y^3}}=\left(\:x^{\frac{2}{7}}\right)\left(y^{-\frac{3}{5}}\right)](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B7%5D%7Bx%5E2%7D%7D%7B%5Csqrt%5B5%5D%7By%5E3%7D%7D%3D%5Cleft%28%5C%3Ax%5E%7B%5Cfrac%7B2%7D%7B7%7D%7D%5Cright%29%5Cleft%28y%5E%7B-%5Cfrac%7B3%7D%7B5%7D%7D%5Cright%29)
Therefore, option 'a' is true.
Step-by-step explanation:
Given the expression
![\frac{\sqrt[7]{x^2}}{\sqrt[5]{y^3}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B7%5D%7Bx%5E2%7D%7D%7B%5Csqrt%5B5%5D%7By%5E3%7D%7D)
Let us solve the expression step by step to get the equivalent
as
![\sqrt[7]{x^2}=\left(x^2\right)^{\frac{1}{7}}](https://tex.z-dn.net/?f=%5Csqrt%5B7%5D%7Bx%5E2%7D%3D%5Cleft%28x%5E2%5Cright%29%5E%7B%5Cfrac%7B1%7D%7B7%7D%7D)
∵ ![\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{a}=a^{\frac{1}{n}}](https://tex.z-dn.net/?f=%5Cmathrm%7BApply%5C%3Aradical%5C%3Arule%7D%3A%5Cquad%20%5Csqrt%5Bn%5D%7Ba%7D%3Da%5E%7B%5Cfrac%7B1%7D%7Bn%7D%7D)
also
![\sqrt[5]{y^3}=\left(y^3\right)^{\frac{1}{5}}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7By%5E3%7D%3D%5Cleft%28y%5E3%5Cright%29%5E%7B%5Cfrac%7B1%7D%7B5%7D%7D)
∵
so the expression becomes
∵ 
Thus, the equivalent will be:
Therefore, option 'a' is true.
I will do my best to answer this question due to the gramatical errors made making it difficult to read and understand.
assuming that the 880 is the number of women employed that makes up 40% of the company employees
880+ (880*1.5) = 2200 employees total
4 is correct. Set up a ratio relationship between similar triangles. 
Answer:
Below in bold
Step-by-step explanation:
∫ dx / (x^2√(9-x^2))
Substitute x = 3sinu and dx = 3cosu du
then the √(9-x^2) = √( 9 - 9sin^2u) = 3 cos u and u = arcsin(x/3)
= 3 ∫(csc^2 u du )/ 27
= 1/9 ∫(csc^2 u du
= -1/9 cot u
= -√9-x^2) / 9x.
