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mestny [16]
4 years ago
14

B={df,g)

Mathematics
1 answer:
aleksley [76]4 years ago
8 0

We have two sets of letters B=\{d,f,g\} and G=\{a,d,h\}.

Intersection of sets B and G is set I that contains elements that are common to B and G, mathematically

I=\{x:x\in B\wedge x\in G\}

Or simply I=B\cap G=\{d\}.

Union if sets B and G is set U that contains elements from B or G thus

U=\{x:x\in B\vee x\in G\}

Or again simply U=B\cup G=\{d,f,g,a,h\}.

Hope this helps.

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(1+cos2x)/(1-cos2x) = cot^2x
sesenic [268]

We will turn the left side into the right side.

\dfrac{1 + \cos 2x}{1 - \cos2x} = \cot^2 x

Use the identity:

\cos 2x = \cos^2 x - \sin^2 x

\dfrac{1 + \cos^2 x - \sin^2 x}{1 - ( \cos^2 x - \sin^2 x)} = \cot^2 x

\dfrac{1 - \sin^2 x + \cos^2 x }{1 - \cos^2 x + \sin^2 x} = \cot^2 x

Now use the identity

\sin^2 x + \cos^2 x = 1 solved for sin^2 x and for cos^2 x.

\dfrac{\cos^2 x + \cos^2 x }{\sin^2 x + \sin^2 x} = \cot^2 x

\dfrac{2\cos^2 x}{2\sin^2 x} = \cot^2 x

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8 0
3 years ago
Identify the coefficient and the exponent for each term of 2x^5– 3x. The coefficients are 5 and 1. The exponents are 2 and - 3.
Ahat [919]

Answer:

The coefficients are 2 and -3

The exponents are 5 and 1

Step-by-step explanation:

Given

2x^5 - 3x

Required

The coefficient and exponent

First, identify the terms.

The terms are: 2x^5 and - 3x

The coefficient are the numbers written before the variables

The exponents are the power of the variables

So; for : 2x^5

Coefficient = 2

Exponent = 5

For - 3x

Coefficient = -3

Exponent = 1

7 0
3 years ago
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5 0
3 years ago
Use the drop-down menus to choose steps in order to correctly solve 1+2b−13=12−4b−2b for b. Pls help
MrMuchimi

b=3

I found this out by subtracting and adding on both sides.

8 0
3 years ago
Read 2 more answers
The area of the following triangle is...?
ArbitrLikvidat [17]

Answer:

A) 24

Step-by-step explanation:

Area of a triangle formula:

A = 0.5bh

Given:

b = 12

h = 4

Work:

A = 0.5bh

A = 0.5(12)(4)

A = 6(4)

A = 24

5 0
3 years ago
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