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3241004551 [841]
4 years ago
12

Outside temperature over a day can be modelled as a sinusoidal function. Suppose you know the high temperature for the day is 75

degrees and the low temperature of 35 degrees occurs at 4 AM. Assuming t is the number of hours since midnight, find an equation for the temperature, D, in terms of t.
Mathematics
1 answer:
AveGali [126]4 years ago
6 0

Answer: D(t) = 20°*cos((pi/4)*t) + 55°

Step-by-step explanation:

using that t = 0 is midnight, we know.

We know:

Max temp = 75°

Min temp = 35° (occurs at t = 4 hours)

Now we can model this as:

D(t) = A*cos(c*t) + B

Where A, c and B are constants.

we have a minimum at t = 4 hours, a minimum means that cos(c*t) = -1

then we have that:

D(4) = A*cos(c*4) + B = A*(-1) + B = 35°

here we also have that cos(c*4) = -1

this means that c*4 = pi

c = pi/4

We also have that the maximum temperature is 75°, the maximum temperature is when cos(c*t) = 1

D(t0) = A*(1) + B = 75°

with this we can find the values of A and B.

-A + B = 35°

A + B = 75°

We isolate B in the first equation and then replace it in the second equation.

B = 35° + A

A + B = 75°

A + 35° + A = 75°

2A = 40°

A = 40°/2 = 20°

B = 35° + 20° = 55°.

Our equation is:

D(t) = 20°*cos((pi/4)*t) + 55°

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HELPPPPPPPPPPPPPPPPPPPPPPPPPPP QUICKKK
Sever21 [200]
Hello again!

We have this equation

x³ - 4x² + 2x + 10 = x² - 5x - 3
All we have to do is follow the steps that we know and remember, when you are doing Algebra make you used the easiest away. You can repeat the same steps over and over as long your answer is correct.

OMG I talked too much!

Ok let's solve this
 
x³ - 4x² + 2x + 10 = x² - 5x - 3
x³ - 4x² + 2x + 10 -x² -5x - 3 = 0
Now again, all we have to do is factorize. Be very careful when you are factorizing.

(x +1)(x² - 6x + 13) = 0
Set factors equal to 0
x + 1= 0 or x² - 6x + 13 = 0
x = -1
This is the answer!


Wait !


I didn't solve x² - 6x + 13 = 0 but I already know I will ended up having NO REAL SOLUTION!


I hope this help again!

A+ Guaranteed! Feel free to comment or message me if you have further questions about the answer.


Peace :)

 


5 0
3 years ago
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