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Nookie1986 [14]

3 years ago

11

Can someone help me please

2 answers:

Tems11 [23]3 years ago

5 0

Answer:

D

Step-by-step explanation:

RUDIKE [14]3 years ago

4 0

Answer:

D

Step-by-step explanation:

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A parabola can be drawn given a focus of (-4,10) and a directrix of y=-4 write the equation of the parabola in any form

sweet-ann [11.9K]

Answer:

$(x+4)^2=28(y-3)$

Step-by-step explanation:

The directrix of the parabola is the horizontal line with the eqaution $y=-4.$ The focus of the parabola is at point (-4,10), than the axis of symmetry of the parabola is the perpendicular line to the directrix passing through the focus. Its equation is $x=-4$

The distance between the directrix and the focus is $|10-(-4)|=14,$ so $p=14$ and the vertex is at point $\left(-4,10-\dfrac{14}{2}\right)\rightarrow (-4,3)$

Parabola goes in positive y-direction, hence its equation is

$(x-x_0)^2=2p(y-y_0),$

where $(x_0,y_0)$ is the vertex, so the equation of this parabola is

$(x+4)^2=28(y-3)$

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3 years ago

Simplify 4/8 pls need help

Ganezh [65]

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3 years ago

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The length of a 200 square foot rectangular vegetable garden is 4feet less than twice the width. Find the length and width of th

inna [77]

Answer:

Length = 18.099 ft

Width = 11.049 ft

Step-by-step explanation:

let the length of the field be x ft

and the width be y ft

as per the condition given in problem

x=2y-4 -----------(A)

Also the area is given as 200 sqft

Hence

xy=200

Hence from A we get

y(2y-4)=200

taking 2 as GCF out

2y(y-2)=200

Dividing both sides by 2 we get

$y(y-2)=100$

$y^2-2y=100$

subtracting 100 from both sides

$y^2-2y-100=0$

Now we solve the above equation with the help of Quadratic formula which is given in the image attached with this for any equation in form

$ax^2+bx+c=0$

Here in our case

a=1

b=-1

c=-100

Putting those values in the formula and solving them for y

$y=\frac{-(-2)+\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}$

$y=\frac{-(-2)-\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}$

Solving first

$y=\frac{2+\sqrt{4+400}{2}$

$y=\frac{2+\sqrt{404}{2}$

$y=\frac{2+20.099}{2}$

$y=\frac{22.099}{2}$

$y=11.049$

Solving second one

$y=\frac{-(-2)-\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}$

$y=\frac{2-\sqrt{4+400}{2}$

$y=\frac{2-\sqrt{404}{2}$

$y=\frac{2-20.099}{2}$

$y=\frac{-18.99}{2}$

$y=-9.045$

Which is wrong as the width can not be in negative

Our width of the field is

y=11.099

Hence the length will be

x=2y-4

x=2(11.049)-4

x=22.099-4

x=18.099

Hence our length x and width y :

Length = 18.099 ft

Width = 11.049 ft

4 0

3 years ago