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3 years ago

If you were creating a timeline, which of the following would appear as the first point?

Geography

1 answer:

Maslowich3 years ago

4 0

Is this multiple choice?

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By definition, two shapes are congruent if you can map one onto the other using rigid transformations (a sequence of one or more

MrRissso [65]

Answer:

The corresponding sides and angles of both the triangles [pre-image and the image] are congruent

Explanation:

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3 years ago

Why are glaciers such effective agents of erosion and deposition?

Elza [17]

They are changing the landscape forms through erosion.
the resulting landforms include glacial cirques, striations, glacial horns, trim lines, U - shaped valleys, sheepback (roches moutonnees), overdeepening (basins or valley were the water can be accumulated) etc

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3 years ago

When languages are grouped together based on common qualities, they are placed into what?

Free_Kalibri [48]

I would say that they are placed into families.

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3 years ago

Read 2 more answers

Explain one reason why some tropical storms<br> intensify into cyclones.

beks73 [17]

They acts as the source of heat and moisture for the formation of deep clouds.As these clouds intensify, strong rising currents of air in the eyewall around the storm centre.

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3 years ago

ACT scores of a sample of UTC students are shown below. Student ACT Score A 22 B 28 C 20 D 21 E 28 F 23 G 26 a. Compute the mean

alisha [4.7K]

Solution :

a). Let x denotes ACT scores.

ACT scores = $\{ 22,28,20,21,28,23,26 \} ; n = 7$

Mean, $(\overline x)=\frac{\sum x_i}{n}$

$=\frac{168}{7}=24$

Sample variance, $S^2=\frac{1}{n-1}\left(\sum x_i^2-n\overline x^2 \right)$

$=\frac{1}{6}(4098-7 \times 24^2)$

$=\frac{66}{6}$

= 11

b). To test whether or not variance of ACT scores of population (say $\sigma^2$ ) of the UTC students is significantly more than 8.

Consider the hypothesis :

$H_0: \sigma^2 \leq8$ vs $H_a: \sigma^2 >8$

It is a right tailed test and α = 0.05

We have

$x^2_{n-1} = \frac{(n-1)s^2}{\sigma^2}$

So test statics is

$x^2_7=\frac{(7-1)11}{8}$

$=\frac{6 \times 11}{8}$

= 8.25

Since our $\text{test statistics is less than the critical value }$ and it falls in a acceptation region, hence we fail to reject $H_0$ and conclude that variance is not greater than 8 significantly.

8 0

3 years ago