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12345 [234]
3 years ago
7

PLEASE HELP I HAVE 10 MINS!! find each side length round to the nearest tenth if necessary

Mathematics
1 answer:
Katen [24]3 years ago
6 0

Answer:

39

Step-by-step explanation:

Use the Pythagorean theorem! So 15^2+36^2=x^2. So x^2=1521 or x=39

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A rental car agency charges $30.00 per day
lutik1710 [3]
<h2>Answer:</h2><h2>They should travel 120 mils in one day for both rental agencies  to cost the same amount to rent</h2>

Step-by-step explanation:

A rental car agency charges $30.00 per day  plus per mile $0.15.

Let x be the number of miles travelled by car

Their total cost = 30 + (0.15x)   ... (1)

Another rental car  agency charges $36.00 per day plus $0.10  per mile

Their total cost = 36 + (0.10x)   ... (2)

Equating (1) and (2), we get

30 + (0.15x) = 36 + (0.10x)

36 - 30 = 0.15x - 0.10x

6 = 0.05x

x = 120 miles

They should travel 120 mils in one day for both rental agencies  to cost the same amount to rent

5 0
3 years ago
Please help with this
xenn [34]

Answer:

Step-by-step explanation:

a

5 0
3 years ago
Read 2 more answers
Someone please help ASAP will give brainliest
sesenic [268]

Answer:

the answer is 2

Step-by-step explanation:

6 0
3 years ago
Sin x degrees= 4/15<br> HELLLPPPPPPPPP PLEASEEEEEEEEE!!!!!
Umnica [9.8K]
From here, just make it inverse:

sin^{-1} ( \frac{4}{15}) = x
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3 0
3 years ago
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Suppose you have 5 riders and 5 horses, and you want to pair them off so that every rider is assigned one horse (and no horse is
maw [93]

There are 120 ways in which 5  riders and 5 horses can be arranged.

We have,

5 riders and 5 horses,

Now,

We know that,

Now,

Using the arrangement formula of Permutation,

i.e.

The total number of ways ^nN_r = \frac{n!}{(n-r)!},

So,

For n = 5,

And,

r = 5

As we have,

n = r,

So,

Now,

Using the above-mentioned formula of arrangement,

i.e.

The total number of ways ^nN_r = \frac{n!}{(n-r)!},

Now,

Substituting values,

We get,

^5N_5 = \frac{5!}{(5-5)!}

We get,

The total number of ways of arrangement = 5! = 5 × 4 × 3 × 2 × 1 = 120,

So,

There are 120 ways to arrange horses for riders.

Hence we can say that there are 120 ways in which 5  riders and 5 horses can be arranged.

Learn more about arrangements here

brainly.com/question/15032503

#SPJ4

7 0
2 years ago
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