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12345 [234]
3 years ago
7

PLEASE HELP I HAVE 10 MINS!! find each side length round to the nearest tenth if necessary

Mathematics
1 answer:
Katen [24]3 years ago
6 0

Answer:

39

Step-by-step explanation:

Use the Pythagorean theorem! So 15^2+36^2=x^2. So x^2=1521 or x=39

You might be interested in
What adds -23 and multiplied to 60
kari74 [83]

Answer:

-20 and -3

Step-by-step explanation:

-20*-3= 60 (remember, two negatives multiplied equals a positive)

-20+-3=-23

Hope this helps!

7 0
3 years ago
18x3 + 6x2y - 9x2 - 3xy <br><br> factor completely
lutik1710 [3]

Answer:

\sf 3x(3x+y)(2x-1)

Step-by-step explanation:

Given expression:

\sf 18x^3 + 6x^2y - 9x^2 - 3xy

Factor out common term \sf 3x:

\sf \implies 3x(6x^2 + 2xy - 3x - y)

Factor \sf (6x^2 + 2xy - 3x - y)

Rearrange:

\sf \implies 6x^2 - 3x+ 2xy  - y

Factor pairs of terms:

\sf \implies 3x(2x-1)+ y(2x  - 1)

Factor out common term (2x - 1):

\sf \implies (3x+y)(2x-1)

Final solution:

\sf \implies 3x(3x+y)(2x-1)

7 0
2 years ago
Jaylynn draw a hen on graph paper using scale of 1 unit on her graph paper represents 5cm.The hen has height of 11 units in the
lisabon 2012 [21]

Answer:

55

Step-by-step explanation:

There are 11 units used on the paper. If each unit is 5cm, that means you can do 11*5 and get 55 cm.

3 0
2 years ago
Read 2 more answers
Graph the equation. (x + 3)2 + (y + 2)2 = 16
Sati [7]

okay well first you should put it in slope-intercept form aka y = mx + b

but you have simplify everything first

2(x + 3) + 2(y + 2) = 16

2x + 3 + 2y + 4 = 16

2x + 2y + 7 = 16

              -7    -7  

2x + 2y = 9

-2x          -2x

2y = -2x + 9

/2         /2

y = -x + 4.5

so now in a graph it should look like this:

3 0
3 years ago
What is the image point of (2,7) after the transformation r y=-x R270?
Semmy [17]

Answer:

0

Step-by-step explanation:|-2 - (-1)| =

|-2 + 1| =

| -1 | =

1.

 

So, we're one unit away from y = -1.  If we're one unit ABOVE y=-1, we need to move the point to be one unit BELOW it instead.  And if we're one unit BELOW y = -1, we need to move the point to be one unit ABOVE it.  

 

Since the point has a y-coordinate of -2, its BELOW the line y = -1, by 1 unit.  Now we change the y-coordinate so its instead ABOVE y = -1, by 1 unit:

 

(y-coordinate of reflection line) + (number of units above that line) =

-1 + 1 =

0.

 

Our new y-coordinate is 0, so the point is now at

(7, 0).

 

A more mechanical, but less intuitive approach is as follows:  

Let L = the y-coordinate of the line, and

P = the y-coordinate of the point.

The new y-coordinate is 2L - P.

In this case, L = -1, and P = -2.  So we have

2L - P =

2(-1) - (-2) =

-2 -(-2) =

0.

5 0
2 years ago
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