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butalik [34]
2 years ago
8

Caan anyone please Tutor me for Geometry please!

Mathematics
1 answer:
strojnjashka [21]2 years ago
3 0
Can someone tutor me too!!!
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Multiply.
Elis [28]

Hey there!

Answer:\boxed{\text{C.}108.73608}

Explanation:

31.246*3.48

Multiply to solve.

\boxed{\text{C.}108.73608}\text{ is your answer.}

Hope this helps!

\text{-TestedHyperr}

4 0
3 years ago
Simplify [0.009÷0.004]-1/2​
pantera1 [17]

Answer:

1.75

Step-by-step explanation:

0.009÷0.004-\frac{1}{2}=

2.25-0.5=

1.75

4 0
3 years ago
Write sixty-five hundredths as a decimal form.
Marat540 [252]

Answer: 0.65

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
You have $1.55 worth of dimes and nickels in a jar. There are 23 coins in the jar. How many dimes do you have? How many nickels
Scilla [17]

i believe the answer is 35 dimes and 65 nickels (sorry if i’m wrong lol)

3 0
3 years ago
Find the volume of the largest rectangular box in the first octant with three faces in the coordinate planes and one vertex in t
makkiz [27]

Answer:

Step-by-step explanation:

x + 2y + 3z = 12

z=\frac{12-x-2y}{3}

Volume = V=f(x,y) = xy(\frac{12-x-2y}{3} )

find partial derivatives using product rule

f_x =\frac{y}{3} (12-2x-2y)\\f_y = \frac{x}{3} (12-x-4y)

i.e.

Using maximum for partial derivatives, we equate first partial derivative to 0.

y=0 or x+y =6

x=0 or x+4y =12

Simplify to get y =2, x = 4

thus critical points are (4,2) (6,0) (0,3)

Of these D the II derivative test gives

D<0 only for (4,2)

Hence maximum volume is when x=4, y=2, z= 4/3

Max volume is = 4(2)(4/3) = 32/3

6 0
3 years ago
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