Answer:
Part A: x^2 + 5x - 8
Part B: 5x^3 + 3x^2 - 6x + 5
Step-by-step explanation:
Part A:
To find the total of side 1 and 2, add the two expressions which represent each side. Combine like terms to simplify.
3x^2 − 2x − 5 + (7x - 2x^2 − 3)
3x^2 - 2x^2 -2x + 7x -5 + -3
x^2 + 5x - 8
Part B:
To solve for the third side of a triangle using its perimeter, subtract the lengths of two of its sides from its perimeter. The perimeter is 5x^3 + 4x^2 − x − 3. Subtract 3x^2 − 2x − 5 and 7x - 2x^2 − 3. The remaining expression is the third side. Combine like terms to simplify.
5x^3 + 4x^2 − x − 3 - (3x^2 − 2x − 5) - (7x - 2x^2 − 3)
5x^3 + 4x^2 - x - 3 - 3x^2 + 2x + 5 - 7x + 2x^2 + 3
5x^3 + (4x^2 -3x^2 + 2x^2) + (-x + 2x - 7x) + (-3 + 5 + 3)
5x^3 + 3x^2 - 6x + 5
Answer:
Step-by-step explanation:
1)
?/10 =4/5
?/5×2 =4/5
4×2/5×2 =8/10 ... the number is : 8
2)
?/4 = 11/4....the number is : 11
Answer:
the equation of the line in slope-intercept form is: 
Step-by-step explanation:
First start by finding the slope of the segment that joins those two points using the general formula for the slope of the segments between two points
and
on the plane:

Then for our case, calling (-4, 6) =
and (-8, 10) =
, we have:

Now, knowing this, we can find the equation of the line by using the "point-slope" form of a line [of slope "m" and going through the point
that tells us:

We will be then using the found slope (-1) and for example one of the given points: (-4 , 6), thus:

Answer:
<em>The actual distance between Rose Lake and the hiking trail is 7 miles.</em>
Step-by-step explanation:
The actual distance between Rose Lake and the main road is 3.5 miles and the scaled distance on the map is 2 inch.
Suppose, the actual distance between Rose Lake and the hiking trail is
miles.
Given that, the scaled distance from Rose Lake to the hiking trail on the map is 4 inch.
So, <u>according to the ratio of "scaled distance" to the "actual distance"</u>, the equation will be......

Thus, the actual distance between Rose Lake and the hiking trail is 7 miles.
Answer:
AB+BE+EF+GF+HG+AH = 14 #EQU 1
BC+CD+DE+EF+GF+BG = 22 #EQU 2
AB+BC+CD+DE+EF+GF+HG+AH = 24 #EQU 3
IMPLEMENTING EQU 2 IN EQU 3
AB+22-EF+ HG+AH = 24 # EQU 5
FROM EQU 1
AB+HG+AH = 14-(BE+EF+GF) #EQU 4
IMPLEMENTING EQU 4 IN EQU 5
22+14 - (BE+EF+GF+EF) = 24
36 - 24 = BE+EF+GF+BG(EF=BG)
12 = PATH TAKEN ON THURSDAY