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jolli1 [7]
4 years ago
15

What is the verticle asymptote horizontal asymptote and domain of f(x)= 6x^2+3 / x-1

Mathematics
1 answer:
sesenic [268]4 years ago
4 0

Domain is x>1 or x<1 vertical asy y=1

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Determine the intervals on which the function is concave up or concave down. (Enter your answers using interval notation. If an
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Step-by-step explanation:

attached is the solution

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Idk my little sister asked me this question but idk how to answer it
PtichkaEL [24]

Answer:

B

Step-by-step explanation:

There are three sets of 60s (3minutes) and if you add 60+60+60 you get 180. Then you take 215-180 and get 35. So 3 minutes and 35 seconds

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4 years ago
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What is Perpendicular to 5x-3y=30 and passing through (-2,7)
alisha [4.7K]

k:y=m_1x+b_1;\ l:y=m_2x+b_2\\\\k\ \perp\ l\iff m_1\cdot m_2=-1\\\\k\ ||\ l\iff m_1=m_2

We have:

k:5x-3y=30\ \ \ \ |-5x\\\\-3y=-5x+30\ \ \ \ |:(-3)\\\\y=\dfrac{5}{3}x-10\to m_1=\dfrac{5}{3}\\\\l:y=m_2x+b\\\\k\ \perp l\Rightarrow \dfrac{5}{3}m_2=-1\ \ \ \ |\cdot\dfrac{3}{5}\\\\m_2=-\dfrac{3}{5}

l:y=-\dfrac{3}{5}x+b

The line l is passing through (-2, 7). Substitute the coordinates of the point to the equation of a line l:

7=-\dfrac{3}{5}\cdot(-2)+b\\\\\dfrac{6}{5}+b=7\ \ \ \ |-\dfrac{6}{5}\\\\b=\dfrac{35}{5}-\dfrac{6}{5}\\\\b=\dfrac{29}{5}

l:y=-\dfrac{3}{5}x+\dfrac{29}{5}\ \ \ \ |\cdot5\\\\5y=-3x+29\ \ \ \ |+3x\\\\3x+5y=29

<h2>Answer: 3x + 5y = 29</h2>
3 0
3 years ago
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Vladimir79 [104]

Answer:

x=-7

Step-by-step explanation:

So we have the equation:

x+5=-2

To solve, subtract 5 from both sides. This is the subtraction property of equality:

(x+5)-5=(-2)-5

The left side cancels:

x=(-2)-5

Subtract on the right.

x=-7

So, our answer is -7.

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3 years ago
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LMN is a straight angle. What is the<br> measure of ZOMP?<br><br> Pls answer ASAP!
zavuch27 [327]

Answer:

<OMP = 76 degrees

Step-by-step explanation:

since LMN is a straight angle, the angles must all add up to 180 degrees.

so 37 + 67 = 104

180 - 104=76 degrees

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3 years ago
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