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stira [4]
3 years ago
7

Please hep I am struggling and this dang hw is due by 9!

Mathematics
2 answers:
Sliva [168]3 years ago
8 0
(9x + 4) * 2x^2


1. Regroup the terms.
2x^2(9x + 4)

2. Expand by distributing the terms.
2x^2 * 9x + 2x^2 * 4

3. Take out the constants.
(2 * 9)x^2x + 2x^2 * 4

4. Simplify 2 * 9 to 18.
18x^2x + 2x^2 * 4

5. Use this product rule: x^ax^b = x^a+b.
18x^2+1 + 2x^2 * 4

6. Simplify 2 + 1 to 3.
18x^3 + 2x^2 * 4

7. Simplify 2x^2 * 4 to 8x^2.
18x^3 + 8x^2




Therefore your answer is:

18x^3 + 8x^2
lora16 [44]3 years ago
3 0

Answer:18x cubed +8x squared

Step-by-step explanation:

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snow_tiger [21]
The two numbers are 12 and 16. 12 + 6 = 18. 6 doubled is 12. 12 plus 6 equals 18. 
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3 years ago
On a piece of paper, graph f(x)=16x0.5^x. Then determine which answer choice matches the graph you drew.
Reil [10]

9514 1404 393

Answer:

  A

Step-by-step explanation:

You can use x=0 and x=1 to find points that must be on the graph.

  f(0) = 16·0.5^0 = 16

  f(1) = 16·0.5^1 = 8

Only graph A matches these points.

7 0
3 years ago
Write 1.68 as a percent.
Ray Of Light [21]

Answer:

1.68 as a percent is 168%.

Step-by-step explanation:

To convert 1.68 to a percentage, multiply the number 1.68 by 100.

4 0
3 years ago
Read 2 more answers
Could someone please explain this problem to me?
disa [49]

Answer:

8/3

Step-by-step explanation:

Because all 4 angles are congruent, the sides are proportional.

the scale factor is 5/30 = 1/6.

meaning x = 16(1/6)=8/3.

7 0
2 years ago
the half life of c14 is 5730 years. Suppose that wood found at an archeological excavation site contains about 35% as much C14 a
Furkat [3]

Answer:

The wood was cut approximately 8679 years ago.

Step-by-step explanation:

At first we assume that examination occured in 2020. The decay of radioactive isotopes are represented by the following ordinary differential equation:

\frac{dm}{dt} = -\frac{m}{\tau} (Eq. 1)

Where:

\frac{dm}{dt} - First derivative of mass in time, measured in miligrams per year.

\tau - Time constant, measured in years.

m - Mass of the radioactive isotope, measured in miligrams.

Now we obtain the solution of this differential equation:

\int {\frac{dm}{m} } = -\frac{1}{\tau}\int dt

\ln m = -\frac{1}{\tau} + C

m(t) = m_{o}\cdot e^{-\frac{t}{\tau} } (Eq. 2)

Where:

m_{o} - Initial mass of isotope, measured in miligrams.

t - Time, measured in years.

And time is cleared within the equation:

t = -\tau \cdot \ln \left[\frac{m(t)}{m_{o}} \right]

Then, time constant can be found as a function of half-life:

\tau = \frac{t_{1/2}}{\ln 2} (Eq. 3)

If we know that t_{1/2} = 5730\,yr and \frac{m(t)}{m_{o}} = 0.35, then:

\tau = \frac{5730\,yr}{\ln 2}

\tau \approx 8266.643\,yr

t = -(8266.643\,yr)\cdot \ln 0.35

t \approx 8678.505\,yr

The wood was cut approximately 8679 years ago.

5 0
3 years ago
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