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3 years ago

-8(-8b-6)=-6b-22 Can someone PLEASE help me I don't understand this at all!!

1 answer:

lina2011 [118]3 years ago

7 0

Do you know the distribution property? I can't explain why you have to do that, but google search it. the number that is outside of the parenthesis will be multiplied in <em>each </em>of the number in the parenthesis.

-8(-8b-6) = -6b-22

the distribution property will look like this

-8 * -8b = 64b

-8 * -6 = 48

(two negative numbers make a positive)

now th equation will look like this

64b + 48 = -6b-22

you must have the variable to one side of the equation. That means you need to subtract one of them to the other side or add it depending if the number is positive or negative. For example, you can add 6b to 64b (the opposite operation of -6b is addtion making -6b a positive number) so 64b + 6b - 70b

70b + 48 = -22

solve b!

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Step-by-step explanation:

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∴ The scale drawing is 1 : 30

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∴ Actual length = (4 × 30)/1 = 120

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3 years ago

Keisha is reading a 325-page book at a rate of 25 pages per day. Use a point-slope equation to determine wheatger she will finis

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she can't finish reading the book in 10 days

Step-by-step explanation:

Given that:

Number of pages = 325

Number of pages read per day= 25

Using the linear relation:

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y = number of pages left

m = reading rate ; c = initial number of pages

y = - 25x + 325

Point slope relation :

y - y1 = m(x - x1)

m = slope

We can factorise the equation to the point slope form:

y - 325 = 25(0 - 10)

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3 years ago

What is the range of the function f(x)=-2|x+1|?

schepotkina [342]

Answer:

The correct answer to given question is option (a).

Step-by-step explanation:

Given function: f(x)= -2|x+1|

we need to put random values of x in given function to see that range of the given function f(x) is all real numbers.

when:

x=0; f(0)= -2|0+1|= -2|1|= -2

when x is positive i.e. x>0

x=1; f(1)= -2|1+1|= -2|2|= -4

x=2; f(2)= -2|2+2|= -2|4|= -8

when x is negative i.e. x<0

x= -1; f(-1)= -2|-1+1|= -2|0| =0

x=-2; f(-2)= -2|-2+1|= -2|-1|=2 (with the help of mod property |-1|=1)

hence, we saw that

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when x<0; f(x)>0

we can conclude from above steps that the range of function f(x)= -2|x+1| is all real numbers.

7 0

4 years ago

Read 2 more answers

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4 years ago

Which is the graph of f(x)=x^2-2x+3

LUCKY_DIMON [66]

Answer:

Step-by-step explanation:

Hello, the vertex is (1,2), right?

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$y=ax^2+bx+c$

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$x=-\dfrac{b}{2a}=\dfrac{-(-2)}{2}=1\\\\1^2-2*1+3=4-2=2$

So this is the first graph.

Thank you

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4 years ago