It would be A. Twelve times. On the first day it was only one inch tall. Then on the sixth it was one foot tall which is twelve inches. Twelve inches is twelve times the amount of one inch.
Answer:
7/12
Step-by-step explanation:
The work done (in foot-pounds) in stretching the spring from its natural length to 0.7 feet beyond its natural length is 1.23 foot-pound
<h3>Data obtained from the question</h3>
From the question given above, the following data were obtained:
- Force (F) = 3 pounds
- Extension (e) = 0.6 feet
- Work done (Wd) =?
<h3>How to determine the spring constant</h3>
- Force (F) = 3 pounds
- Extension (e) = 0.6 feet
- Spring constant (K) =?
F = Ke
Divide both sides by e
K = F/ e
K = 3 / 0.6
K = 5 pound/foot
Thus, the spring constant of the spring is 5 pound/foot
<h3>How to determine the work done</h3>
- Spring constant (K) = 5 pound/foot
- Extention (e) = 0.7 feet
- Work done (Wd) =?
Wd = ½Ke²
Wd = ½ × 5 × 0.7²
Wd = 2.5 × 0.49
Wd = 1.23 foot-pound
Therefore, the work done in stretching the spring 0.7 feet is 1.23 foot-pound
Learn more about spring constant:
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Area of rectangle it's the width multiply by the lenth.
A=W*L
A=38 1/4 m²
W=4 1/2 m²
So: 38 1/4 = 4 1/2 * L
Dividing both sides by 4 1/2: : 4 1/2 :4 1/2
Answer: T<span>he length of the garden is 8 1/2 meters</span>
$97
This is because he will owe the amount of the check $52, plus he will also owe the two fees which will total $45
