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STatiana [176]
3 years ago
6

Write an equation to represent the linear relationship in the table

Mathematics
1 answer:
WINSTONCH [101]3 years ago
7 0

Answer:

-1/2

Step-by-step explanation:

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Write the equation of the line that has a slope of m=3 and passes through (4 , 2)
mina [271]

Answer:

y=3x-10

Step-by-step explanation:

For this, you would use the point slope formula, which is (y-y1)=m(x-x1). x1 and y1 are the coordinates from the ordered pair.

(y-y1)=m(x-x1)

(y-2)=3(x-4)

y-2=3x-12

y=3x-10

To check, you can plug the coordinates into the equation.

y=3x-10

(2)=3(4)-10

2=12-10

2=2

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3 years ago
Please help sill reward 10 points
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Write y=3/5x+4 in standard form using integers
Naily [24]
Just move y to the side with x and move 4 to the other end
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Using the correct graph, describe the association shown. Will mark brainliest❤️
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Answer:

it is linear association

Step-by-step explanation:

3 0
3 years ago
Use the definition of taylor series to find the taylor series (centered at
Alexxandr [17]
Cos(x) is infinitely differentiable, can be expanded using Taylor's series.
The series about c can be expressed as
f(x)=\sum_{n=0}^{\infty}\frac{f^{n}(c)}{n!}(x-c)^n
Substituting cos(x), c= π /4,we have
cos(x)=\sum_{n=0}^{\infty}\frac{f^{n}(\frac{\pi}{4})}{n!}(x-\frac{\pi}{4})^n
and since
f'(\frac{\pi}{4})=-sin(\frac{\pi}{4})=-\sqrt{2}/2
f"(\frac{\pi}{4})=-cos(\frac{\pi}{4})=-\sqrt{2}/2
f^{(iii)}(\frac{\pi}{4})=sin(\frac{\pi}{4})=\sqrt{2}/2
f^{(iv)}(\frac{\pi}{4})=cos(\frac{\pi}{4})=\sqrt{2}/2

we can simplify the expansion to 
cos(x)=\frac{\sqrt{2}}{2}(1-(x-\frac{\pi}{4})/1!-(x-\frac{\pi}{4})^2/2!+(x-\frac{\pi}{4})^3/3!+(x-\frac{\pi}{4})^4/4!-(x-\frac{\pi}{4})^5/5!-...)
Note that the sign pattern is  - - + + - - + + - - ..... following the sign pattern of the derivatives of cos(x).
5 0
3 years ago
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