Assuming metric units, metre, kilogram and seconds
Best approach: draw a free body diagram and identify forces acting on the child, which are:
gravity, which can be decomposed into normal and parallel (to slide) components
N=mg(cos(theta)) [pressing on slide surface]
F=mg(sin(theta)) [pushing child downwards, also cause for acceleration]
m=mass of child (in kg)
g=acceleration due to gravity = 9.81 m/s^2
theta=angle with horizontal = 42 degrees
Similarly, kinetic friction is slowing down the child, pushing against F, and equal to
Fr=mu*N=mu*mg(cos(theta))
mu=coefficient of kinetic friction = 0.2
The net force pushing child downwards along slide is therefore
Fnet=F-Fr
=mg(sin(theta))-mu*mg(cos(theta))
=mg(sin(theta)-mu*cos(theta)) [ assuming sin(theta)> mu*cos(theta) ]
From Newton's second law,
F=ma, or
a=F/m
=mg(sin(theta)-mu*cos(theta)) / m
= g(sin(theta)-mu*cos(theta)) [ m/s^2]
In case imperial units are used, g is approximately 32.2 feet/s^2.
and the answer will be in the same units [ft/s^2] since sin, cos and mu are pure numbers.
Answer:
I think its B.) Yes, because the ratios simplify to the same number., sorry if it's wrong
Step-by-step explanation:
50/10 = 1/5
60/12 = 1/5
70/14 = 1/5
80/16 = 1/5
They all simplify to the same proportion.
Answer:
Sorry I really don't know :(
Step-by-step explanation:
Very sorry
Option A: >
Solution:
Given a triangle GHJ.
The line GH is perpendicular to line HJ.
This means the triangle is a right angled triangle.
In ΔGHJ, GH is the base of the triangle and
HJ is a height of the triangle.
Then the third side must be the hypotenuse of the right triangle.
We know that by the Pythagoras theorem,


This clearly shows that the hypotenuse is greater than the height.
⇒ GJ > HJ
Option A: > is the correct answer.
If line GH is perpendicular to line HJ, then GJ is > HJ.
Answer:
x= -9/7
y= -38/7
so it has A. exactly one solution
Step-by-step explanation:
Substitute into one of the equations: 5x+1= -2x-8
Rearrange unknown terms to the left side of the equation: 5x+2x=-8-1
Combine like terms:7x=-8-1
Calculate the sum or difference: 8x=-9
Divide both sides of the equation by the coefficient of variable: x=-9/7
Substitute into one of the equations:y=-2×(-9/7)-8
Write as a single fraction:y=2×9/7-8
Calculate the product or quotient:y=18/7 -8
Convert the expression into a fraction: y=18/7 -8/1
Expand the fraction to get the least common demominator:y=18/7-8x7/1x7
Calculate the product or quotient: y=18/7-56/7
Write the numerators over common denominator:y=18-56/7
Calculate the sum or difference: y=-38/7
Rewrite the fraction: y= -38/7
The solution of the system is:
x= -9/7
y= -38/7