Depending on how many wreaths his has the least he could put on each wreath is 2 but the most he could put on is 6
The number of ways to select 4 digits from 10 digits is
₁₀C₄ = 10!/(4!*6!)
= (10*9*8*7*6!)/(4*3*2*1*6!)
= (10*9*8*7)/(4*3*2)
= 210
If order is not important, the number of arrangements of 6,7,8,9 in any order is
4! = 4*3*2*1
= 24
The probability that these 4 digits are assigned is
24/210 = 0.1143
-4 | x + 5 | = -16...divide both sides by -4, eliminating it on the left side
| x + 5 | = -16/-4
| x + 5 | = 4
x + 5 = 4 -(x + 5) = 4
x = 4 - 5 -x - 5 = 4
x = -1 -x = 4 + 5
-x = 9
x = -9
solutions : x = -1 , x = -9
Answer:
#1 and # 3 maybe
Soooooooory if this wrong, This is the type of question I would get stuck on... O////O