Approximetly 60 credit hours which equates to approximately 2 years.
Answer:
k = 28/5
General Formulas and Concepts:
<u>Pre-Algebra</u>
- Order of Operations: BPEMDAS
- Equality Properties
Explanation:
<u>Step 1: Define</u>
10/7 = 8/k
<u>Step 2: Solve for </u><em><u>k</u></em>
- Cross-multiply: 10k = 56
- Isolate <em>k</em>: k = 56/10
- Simplify: k = 28/5
<u>Step 3: Check</u>
<em>Plug in k to verify it's a solution.</em>
- Substitute: 10/7 = 8/28/5
- KCF: 10/7 = 40/8
- Simplify: 10/7 = 10/7
Here we see that 10/7 does indeed equal 10/7.
∴ k = 28/5 is a solution of the equation.
1) x=9, because we can use the Pythagorean theorem, x^2 + 144 = 225, x^2 = 81
2) , because 6^2 +6^2 = 72,
3) , because
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