Question

{x}^{2}-10x+21=0x Solve and explain step by step thanks

Answer 1

Answer:

x = 3, x = 7

Step-by-step explanation:

Assuming you require the solution to this quadratic equation.

Given

x² - 10x + 21 = 0

Consider the factors of the constant term (+ 21) which sum to give the coefficient of the x- term (- 10)

The factors are - 7 and - 3, since

- 7 × - 3 = 21 and - 7 - 3 = - 10, thus

x² - 10x + 21 = 0 ← in standard form

(x - 7)(x - 3) = 0 ← in factored form

Equate each factor to zero and solve for x

x - 3 = 0 ⇒ x = 3

x - 7 = 0 ⇒ x = 7

Answer 2

Answer:

x = 3,7

Step-by-step explanation:

x² - 10x + 21 = 0

x² - 7x - 3x + 21 = 0

x(x - 7) - 3(x - 7) = 0

(x - 3)(x - 7) = 0

x = 3, 7

Means the graph cuts the x-axis at 3 and 7