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Cerrena [4.2K]
3 years ago
5

StartFraction 47 Over 39 EndFraction = StartFraction b Over 2 EndFraction

Mathematics
1 answer:
statuscvo [17]3 years ago
3 0

Answer:

2.41

Step-by-step explanation:

Cross multiplication

47(2)=39b

94÷39=39b÷39

2.41=b

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I need help with this problem. Given: BC = 10 inches AC = √50 inches m∠CBD = 60° m∠CAD = 90° Calculate the exact area of the sha
Nikitich [7]

Answer:

Area of the shaded region = 23.33 in²

Step-by-step explanation:

Area of a sector = \frac{\theta}{360}(\pi r^{2})

Where θ = Central angle subtended by an arc

r = radius of the circle

Area of the sector BCD = \frac{60}{360}(\pi) (10^{2})

                                       = 52.36 in²

Area of equilateral triangle BCD = \frac{\sqrt{3} }{4}(\text{Side})^2

                                                      = \frac{\sqrt{3} }{4}(10)^2

                                                      = 25\sqrt{3} in²

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                                                             = 9.06 in²

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Area of right triangle CAD = \frac{1}{2}(\text{Base})(\text{Height})

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                                            = \frac{1}{2}(\sqrt{50})(\sqrt{50})

                                            = 25 in²

Area of the shaded part in the ΔACD = 39.27 - 25

                                                                         = 14.27 in²

Area of the shaded part of the figure = 9.06 + 14.27

                                                                = 23.33 in²

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