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Kisachek [45]
3 years ago
14

Draw and classify the polygon with the given vertices. Find the perimeter and the area of the polygon. M(-2,5), N(3,-2), P(-2,-2

)

Mathematics
2 answers:
Nadusha1986 [10]3 years ago
5 0

Answer:

<em>Perimeter = 20.6cm  to 1dp  = 20.60cm to 2dp</em>

<em>Area = Base = 8.6/2 = 4.3 x 4.069  = 17.5cm^2</em>

<em>Height is found 4.07  cos( 54.47deg) 5/8.6 = 4.069cm</em>

Step-by-step explanation:

<em>Right angle side triangle, sides </em>

<em>= MN =8.6cm </em>

<em>= NP=5cm </em>

<em>= PM=7cm </em>

<em>= 25sq + 49sq = 74sq</em>

<em>MN^2 =√74 = 8.60232526704 = 8.6cm</em>

<em>P = 8.6 + 5 + 7 = 20.6cm </em>

forsale [732]3 years ago
5 0

Answer:

  • see below for a drawing
  • right triangle
  • perimeter = 20.6 units
  • area = 17.5 units²

Step-by-step explanation:

A graph shows the figure to be a right triangle with a base of 5 units and a height of 7 units. Its hypotenuse will be given by the Pythagorean theorem:

  MN² = MP² +PN²

  MN² = 7² +5² = 74

  MN = √74 ≈ 8.60

__

The perimeter is the sum of the side lengths:

  Perimeter = MN +MP +PN = 8.60 +7 +5

  Perimeter = 20.60 . . . . units

__

The area is given by the area formula:

  Area = 1/2bh = 1/2·5·7 = 35/2

  Area = 17.5 . . . . square units

The polygon is a right triangle with a perimeter of 20.60 units and an area of 17.5 square units

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Step-by-step explanation:

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The amount of paper that the copy shop used this month was a 25% increase of the amount of paper they used last month. What perc
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Answer:

You didn't include any image here, but numerically, the amount of paper consumed this month is 125% compared to last month.

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If last month's consumption is represented by 8 equal shapes, then the current month's consumption will be 10 shapes.  

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3 years ago
A man is standing at a radar base and observes an unidentified plane at an altitude 6000m flying towards the radar base at an an
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Answer:

The speed in of the plane is 115.47 m/sec

Step-by-step explanation:

Given:

Height at which the plane is flying = 6000 m

Angle of elevation at the radar base = 30 Degrees

Angle of elevation at the radar base after one minute  = 60 Degrees

To Find:

The Speed of the plane in meter per second = ?

Solution:

Let us use the tangent of the angle to find the distance (d) to a point directly below plane:

<u>when the angle is 30 degrees</u>

tan(30) = \frac{6000}{d1}

d1   = \frac{6000}{tan(30)}

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tan(60) = \frac{6000}{d2}

d2  = \frac{6000}{tan(60)}

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4 0
3 years ago
A demographer wants to measure life expectancy in countries 1 and 2. Let μ1 and μ2 denote the mean life expectancy in countries
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Answer:

For this case we want to test if life expectancy in country 1 is more than 10 years lower than in country 2, (alternatibe hypothesis), so then the system of hypothesis are:

Null hypothesis: \mu_1 \leq \mu_2 -10

Alternative hypothesis:\mu_1 > \mu_2 -10

Or equivalently:

Null hypothesis: \mu_1 - \mu_2 \leq 10

Alternative hypothesis:\mu_1 - \mu_2 >10

Step-by-step explanation:

Previous concepts

A hypothesis is defined as "a speculation or theory based on insufficient evidence that lends itself to further testing and experimentation. With further testing, a hypothesis can usually be proven true or false".  

The null hypothesis is defined as "a hypothesis that says there is no statistical significance between the two variables in the hypothesis. It is the hypothesis that the researcher is trying to disprove".

The alternative hypothesis is "just the inverse, or opposite, of the null hypothesis. It is the hypothesis that researcher is trying to prove".

Solution to the problem

For this case we want to test if life expectancy in country 1 is more than 10 years lower than in country 2, (alternatibe hypothesis), so then the system of hypothesis are:

Null hypothesis: \mu_1 \leq \mu_2 -10

Alternative hypothesis:\mu_1 > \mu_2 -10

Or equivalently:

Null hypothesis: \mu_1 - \mu_2 \leq 10

Alternative hypothesis:\mu_1 - \mu_2 >10

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Sedbober [7]

Answer:

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Step-by-step explanation:

I find it takes less work if I can eliminate obviously wrong answers. Toward that end, we can consider the constant terms only:

  1. -3 +(-2) = -5 . . . . possible equivalent
  2. -10 -5 = -15 . . . . NOT equivalent
  3. 3(-5) -2(5) = -25 . . . . NOT equivalent
  4. -9 -(-4) = -5 . . . . possible equivalent
  5. -7 -(-5) = -2 . . . . NOT equivalent
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Now, we can go back and check the other terms in the candidate expressions we have identified.

  1. (-16x² +10x -3) +(4x² -29x -2) = (-16+4)x² +(10-29)x -5 = -12x² -19x -5 . . . OK

  4. (2x² -11x -9) -(14x² +8x -4) = (2-14)x² +(-11-8)x -5 = -12x² -19x -5 . . . OK

  6. 2(x -1) -3(4x² +7x +1) = -12x² +(2 -3·7)x -5 = -12x² -19x -5 . . . OK

All three of the "possible equivalent" expressions we identified on the first pass are fully equivalent to the target expression. These are your answer choices.

7 0
3 years ago
Read 2 more answers
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