Answer: 0.86 of the exam scores are between 68 and 77.99 points
Step-by-step explanation:
Since the set of computer science exam scores are normally distributed, we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = computer science exam scores .
µ = mean score
σ = standard deviation
From the information given,
µ = 71.33 points
σ = 3 points
We want to find the proportion of the exam scores are between 68 and 77.99 points. It is expressed as
P(68 ≤ x ≤ 77.99)
For x = 68,
z = (68 - 71.33)/3 = - 1.11
Looking at the normal distribution table, the probability corresponding to the z score is 0.13
For x = 68,
z = (77.99 - 71.33)/3 = 2.22
Looking at the normal distribution table, the probability corresponding to the z score is 0.99
P(68 ≤ x ≤ 77.99) = 0.99 - 0.13 = 0.86
The answer would be true because a polynomial consists of many terms and a trinomial has three terms.
The first thing you should do in this case is to write the expression correctly:
- (1/9) y + (1/3)
Now, we take out common factor (1/9) obtaining:
1/9 (-y + 3)
Let's check:
1/9 (-y + 3)
-1/9y + 3/9
-1/9y + 1/3
OK
Answer:
An expression equivalent is:
1/9 (-y + 3)
Answer:
Step-by-step explanation: Your supposed to move 1.5x to the other side of 2y. Then you have -1.5x on the right side. Divide all terms by 2 and you’ll get your equation in y=mx+b format. Hope this helps
Answer:
The linear function would be f(x) = 4x - 10
Step-by-step explanation:
In order to find this, we need to take the equation and solve it for y.
y - 2 = 4(x - 3)
y - 2 = 4x - 12
y = 4x - 10
Now we replace the y with f(x) and this is the function.
f(x) = 4x - 10
