First subtract the x variable on both sides so on the first equation youll have -6y=8x+60 then divide 6 on all variables which means youll have y=8/6x+10 and in the second equation you do the same thing and youll have y=-5/6x-11.5
Y=6x+1
y=6(5)+1
y=30+1
y=31
D. (5, 31)
hope this helps!
Answer:
15.5
Step-by-step explanation:
16.5-10
=15.5
So 15.5 is the range
Answer:
x = 5
y = 11
Step-by-step explanation:
y = 4x - 9
2x -3(4x - 9) = -23
2x - 12x + 27 = -23
-10x = -23 -27
-10x = -50
minus cancels out
x = 5
y = 4(5) -9
y = 20 - 9
y = 11
Answer:
(D) t^4
Step-by-step explanation:
You have defined ...
a3 = a2·a1
a4 = a3·(a2·a1) = a3²
a5 = a4·(a3·a2·a1) = a4² = (a3²)² = a3⁴
Then if a3 = t, a5 = t⁴