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3 years ago

How many solutions does this equation have?

Mathematics

2 answers:

IgorLugansk [536]3 years ago

4 0

Answer:

Step-by-step explanation:

maria [59]3 years ago

3 0

One solution and it’s -1

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Math work please help wioth my math

Juli2301 [7.4K]

Answer:

Figure A is scalene and probably obtuse.

Figure B is scalene and right.

Figure C is equilateral and acute.

Figure D is isosceles and right.

Figure E is isosceles and acute.

I am so sorry if I did a few wrong, I'm in Middle-School so I don't know much. I hope I get everything correct!

7 0

3 years ago

Read 2 more answers

To support a tree damaged in a storm, a 12-foot wire is secured from the ground to the tree at a point 10 feet off the ground. T

VARVARA [1.3K]

Answer:

(D)56.4

Step-by-step explanation:

According to the question, Let AB=10, AC=12 and m∠B=90°.

Thus, from ΔABC, using trigonometry, we have

$\frac{AB}{AC}=sinx$

$\frac{10}{12}=sinx$

$\frac{5}{6}=sinx$

$sinx=0.83$

$x=sin^{-1}(0.83)$

$x=56.4$

Therefore, at $x=56.4$ the wire meet the ground.

8 0

3 years ago

Please help, i need to raise my grade <br>solve for v

zhenek [66]

Answer:

2(s-c)/ a^2 = v

Step-by-step explanation:

s = 1/2 a^2 v+c

Subtract c from each side

s -c = 1/2 a^2 v+c-c

s-c = 1/2 a^2 v

Multiply each side by 2

2(s-c) = 2* 1/2 a^2 v

2(s-c) = a^2 v

Divide each side by a^2

2(s-c)/ a^2 = a^2 v /a^2

2(s-c)/ a^2 = v

8 0

3 years ago

Whats the unit rate of 122 and 4?

ANTONII [103]

Answer: 30.5

Step-by-step explanation:

30.5 times 4 equals 122

5 0

3 years ago

A student earned grades of 79, 74, and 73 on her three regular exams. She earned a grade of 66 on the final exam and 88 on her c

navik [9.2K]

Answer:

The weighted mean grade is 78.62

Step-by-step explanation:

We are given the following in the question:

Regular exam score = 79, 74, and 73

Weightage of regular exam = 12%

Final exam grade = 66

Weightage of final exams = 17%

Course project grade = 88

Weightage of project = 10%

Homework grade = 93

Weightage of homework = 37%

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

Mean of regular exam scores =

$Mean =\displaystyle\frac{226}{3} = 75.33$

Weighted mean grade

$w = \dfrac{\sum wx}{\sum w}$

$\displaystyle\sum wx =\displaystyle\frac{12}{100}\times 75.33 + \frac{17}{100}\times 66 + \frac{10}{100}\times 88 + \frac{33}{100}\times 93\\\\\displaystyle\sum wx = 59.75\\\\\sum w = 0.12 + 0.17 + 0.10 + 0.37 = 0.76\\\\w = \frac{59.75}{0.76} = 78.62$

The weighted mean grade is 78.62

8 0

3 years ago