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Romashka-Z-Leto [24]
3 years ago
8

The scores on a test are normally distributed with a mean of 110 and a standard deviation of 22. What is the score that is 3 sta

ndard deviations below the​ mean?
Mathematics
1 answer:
Alborosie3 years ago
7 0

Answer:

Step-by-step explanation:

If the mean is 110, and the standard devaition is 22,

1 standard dev. below the mean is 110-22

2  standard dev below the mean is 110-22-22

3 standard dev below the mean is 110-22-22-22

Hope that helps!

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Thrice a number subtracted from 10?​
Mkey [24]

Answer:

10-3x

Step-by-step explanation:

let the number=x

thrice the number becomes 3x

7 0
2 years ago
the patient recovery time from a particular surgical procedure is normally distributed with a mean of 5.9 days and a standard de
NNADVOKAT [17]
The 85th percentile is the cutoff time t such that

\mathbb P(X

In other words, the 85th percentile refers to the time needed to belong to the top 15% of the distribution; more generally, the n percentile is the top (100-n)\% of the distribution.

Anyway, to find this value of t, transform X to a random variable Z with the standard normal distribution using

Z=\dfrac{X-\mu}\sigma

where \mu is the mean of X and \sigma is the standard deviation of X.

\mathbb P(X

Here t^* is used to denote the z-score corresponding to the cutoff time t. Referring to a z-score table, you find that this occurs for t^*\approx1.036. So,

\dfrac{t-5.9}{2.1}=t^*\implies t=5.9+2.1t^*\approx8.076
7 0
3 years ago
1. The cost of 5 squash and 2 zucchini is $1.32. Three squash and 1 zucchini cost $0.75. Find the cost of each vegetable.
kogti [31]
Squash = s
zucchini = z

5s+2z = 1.32 ---(1)
3s+z = 0.75 ----(2)

2*(2); 6s+2z = 1.50 ---(3)
(3)-(1); s = 1.50-1.32= 0.18
then 3s + z = 0.75
3(0.18) + z = 0.75
0.54 + z = 0.75
so z = 0.75 - 0.54 = 0.21

so that the cost of squash is $0.18 and the cpst of zucchini is $0.21
4 0
3 years ago
For the vectors u= (1, 3, 2) and v=(2, 0, 3)​, evaluate the following expressions.
Ratling [72]

Answer:

a) 4u + 2v = (8, 12, 14)

b) 2u - v = (0, 6, 1)

c) |u + 4v| = 16.9

Step-by-step explanation:

When we add/subtract vectors, we add/subtract their components. For example

a = (a1,a2,a3)

b = (b1,b2,b3)

a+b = (a1 + b1, a2 + b2, a3 + b3)

|a| is the modulus of vector a, given by

|a| = \sqrt{a1^{2} + a2^{2} + a3^{3}}

In this problem, we have that:

u = (1,3,2)

v = (2,0,3)

(a) 4u+2v

4u = 4(1,3,2) = (4,12,8)

2v = 2(2,0,3) = (4,0,6)

4u + 2v = (8, 12, 14)

(b) 2u-v

2u = 2(1,3,2) = (2,6,4)

v = (2,0,3)

2u - v = (0, 6, 1)

(c) |u + 4v|

u = (1,3,2)

4v = 4(2,0,3) = (8,0,12)

u + 4v = (9,3,14)

|u + 4v| = \sqrt{9^{2} + 3^{2} + 14^{2}} = 16.9

7 0
3 years ago
Jessica has an account with a credit union. Her account earns 2.1% simple interest yearly. Exactly a year and a half ago, she op
kkurt [141]
<span>
$28.35 because if she earns 2.1% interest yearly than she will earn 3.15% for 1 1/2 years multiply 0.0315 by 900 and you will get 28.35</span>

7 0
3 years ago
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