All categories

3 years ago

The digit in each place has a value that is

1 answer:

7 0

ok lets say the number is 375 ok so the five is in the ones place so its worth only 5 the seven is in the tenths place its worth would be 70 and all you had to was multiply the number times 10 because it in the tenths place ok moving on the 3 is in he hundreds place so its worth 300 why because all you have to do is multiply the number in the hundreds by one hundreds

You might be interested in

A conference consists of 5 sessions: A, B, C, D, and E. Here are the costs of the sessions.

Morgarella [4.7K]

$200 ABC
50+50+100=200

5 0

3 years ago

Read 2 more answers

Giving brainliest! need this one question soon, thank you so much!

Novosadov [1.4K]

Answer:

7.014m

Step-by-step explanation:

$\frac{11.3}{2.9} = \frac{h}{1.8} \\ h = \frac{11.3 \times 1.8}{2.9} \\ h = 7.013793103448275 \\ h = 7.014m$

please rate brainliest

5 0

3 years ago

A line segment BK is an angle bisector of ΔABC. A line KM intersects side BC such, that BM = MK. Prove: KM ∥ AB.

weqwewe [10]

Answer:

∠BKM= ∠ABK

Therefore AB ║KM (∵ ∠BKM= ∠ABK and lies between AB and KM and BK is the transversal line)

m∠MBK ≅ m∠BKM (Angles opposite to equal side of ΔBMK are equal)

Step-by-step explanation:

Given: BK is an angle bisector of Δ ABC. and line KM intersect BC such that, BM = MK

TO prove: KM ║AB

Now, As given in figure 1,

In Δ ABC, ∠ABK = ∠KBC (∵ BK is angle bisector)

Now in Δ BMK, ∠MBK = ∠BKM (∵ BM = MK and angles opposite to equal sides of a triangle are equal.)

Now ∵ ∠MBK = ∠BKM

and ∠ABK = ∠KBM

∴ ∠BKM= ∠ABK

Therefore AB ║KM (∵ ∠BKM= ∠ABK and BK is the transversal line)

Hence proved.

8 0

4 years ago

Read 2 more answers

If you can, give the explanation. I'm finding these very difficult.

Goryan [66]

Answer:

Gustavo

Step-by-step explanation:

if anything this looks like 38-19n, if the first term is n=1.

But as that isn't an option, gustavo should be correct, as his sequence would go down by 19 each time (yuki's would go up by 19 each time, not down like the sequence shows)

3 0

3 years ago

Please help answer these questions

vfiekz [6]

Step 1

given

Step 2

$\angle HKM \cong \angle OKM, \angle HMK \cong \angle OMK$

Step 3

$\overline{KM} \cong \overline{KM}$

Reason: Reflexive property

Step 4

ASA

8 0

2 years ago