Hi there! The answer is C. h = 6 or h = −7
![{h}^{2} - 42 = - h](https://tex.z-dn.net/?f=%20%7Bh%7D%5E%7B2%7D%20-%2042%20%3D%20-%20h)
Add h to both sides of the equation.
![h {}^{2} + h - 42 = 0](https://tex.z-dn.net/?f=h%20%7B%7D%5E%7B2%7D%20%2B%20h%20-%2042%20%3D%200)
First we need to find the discriminant (which can be found using the formula D = b^2 - 4ac)
![d = 1 {}^{2} - 4 \times 1 \times - 42 \\ d = 1 + 168 \\ d = 169](https://tex.z-dn.net/?f=d%20%3D%201%20%7B%7D%5E%7B2%7D%20-%204%20%5Ctimes%201%20%5Ctimes%20-%2042%20%5C%5C%20d%20%3D%201%20%2B%20168%20%5C%5C%20d%20%3D%20169)
Now we can plug in our found values into the quadratic formula.
![x = \frac{ - b - \sqrt{d} }{2a} \: \\ or \\ \: x = \frac{ - b + \sqrt{d} }{2a}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B%20-%20b%20-%20%5Csqrt%7Bd%7D%20%7D%7B2a%7D%20%5C%3A%20%5C%5C%20or%20%5C%5C%20%5C%3A%20x%20%3D%20%5Cfrac%7B%20-%20b%20%2B%20%5Csqrt%7Bd%7D%20%7D%7B2a%7D%20)
Plug in.
![x = \frac{ - 1 - \sqrt{196} }{2 \times 1} = \frac{ - 1 - 13}{2} = \frac{ - 14}{2} = - 7 \\ or \\ x = \frac{ - 1 + \sqrt{196} }{2 \times 1} = \frac{ - 1 + 13}{2} = \frac{ 12}{2} = 6](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B%20-%201%20-%20%5Csqrt%7B196%7D%20%7D%7B2%20%5Ctimes%201%7D%20%3D%20%5Cfrac%7B%20-%201%20-%2013%7D%7B2%7D%20%3D%20%5Cfrac%7B%20-%2014%7D%7B2%7D%20%3D%20-%207%20%5C%5C%20or%20%5C%5C%20x%20%3D%20%5Cfrac%7B%20-%201%20%2B%20%5Csqrt%7B196%7D%20%7D%7B2%20%5Ctimes%201%7D%20%3D%20%5Cfrac%7B%20-%201%20%2B%2013%7D%7B2%7D%20%3D%20%5Cfrac%7B%2012%7D%7B2%7D%20%3D%206)
Hence, the answer is C. h = 6 or h = −7
Answer:
I got 28
Step-by-step explanation:
I use the slope formula
![\frac{y2-y1}{x2-x1}](https://tex.z-dn.net/?f=%5Cfrac%7By2-y1%7D%7Bx2-x1%7D)
![\frac{224-140}{8-5} =\frac{84}{3} =28](https://tex.z-dn.net/?f=%5Cfrac%7B224-140%7D%7B8-5%7D%20%3D%5Cfrac%7B84%7D%7B3%7D%20%3D28)
Answer:
I think that it is B buuut I am not to sure
Step-by-step explanation: