One way to write 18/6 is to compute 18/6 to be the whole number of a quotient that is equal to. Another way to write 18/6 is to write it as an improper fraction that's reduced. One more way to write 18/6 is as a decimal. Note how all of these ways of writing the same expression are all equal to writing one same value, and it's the WAY in which you modify what you're writing.
See, to make a 5-letter word , 5 places are to be filled ___ ___ ___ ___ ___ 1st 2nd 3rd 4th 5th the first place can be filled in 5 ways (s,p,e,l,l) 2nd place in 4 ways. 3rd place in 3 ways. 4th place in 2 ways. 5th place in 1 way. now , ther are 2L's. hence total no. of words that can be formed=(5*4*3*2*1) / 2*1
Answer:
A = 57°
B = 19°
C = 104°
Step-by-step explanation:
We have a triangle with 3 angles:
A, B, and C.
We know that:
"Angle A is 3 times larger than angle B"
We can write this as:
A = 3*B
"Angle C was 10° less than 6 times angle B"
This can be written as:
C = 6*B - 10°
And we also know that the sum of all interior angles of a triangle is 180°
Then we also have the equation:
A + B + C = 180°
So we have a system of 3 equations:
A = 3*B
C = 6*B - 10°
A + B + C = 180°
To solve this, the first step is to isolate one of the variables in one of the equations.
We can see that A is already isolated in the first one, so we can skip that step.
Now we need to replace A in the other equations, to get:
C = 6*B - 10°
(3*B) + B + C = 180°
Now we have a system of two equations.
Let's do the same procedure, we can see that C is isolated in the top equation, so we can just replace that in the other equation to get:
3*B + B + (6*B - 10°) = 180°
Now we can solve this for angle B
4*B + 6*B - 10° = 180°
10*B - 10° = 180°
10*B = 180° + 10° = 190°
B = 190°/10 = 19°
Now that we know the measure of angle B, we can input this in the equations:
A = 3*B
C = 6*B - 10°
To find the measures of the other two angles:
A = 3*19° = 57°
C = 6*19° - 10° = 104°
6/5 because flip the second number and multiply when dividing fractions.
