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Kryger [21]
3 years ago
15

Which of the following are binomials?

Mathematics
2 answers:
Wewaii [24]3 years ago
8 0
D and E are both binomials because they both have two terms
levacccp [35]3 years ago
5 0

Answer:

so, I believe D and E, are Binomials.

Step-by-step explanation:

Bi- is 2

Mono- is 1

Hope my answer has helped you and if not i'm sorry.

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Write a word problem for the equation. <br> 1/2 (x-4) = 1/3x + 2
Ganezh [65]

Answer:

Half the age of Carlos four years ago is 2 years more than one-third his current age.

Step-by-step explanation:

We want to write a word problem for the equation.

\frac{1}{2} (x - 4) =  \frac{1}{3}x + 2

Let x represent the present age of Carlos.

Four years ago, Carlos was x-4 years.

Half his age four years ago is ½(x-4)

Two years more than one-third his current age is ⅓x+2

3 0
3 years ago
Solve 7x-2y=11 for y
Leni [432]

Answer:

y = 7/2x -11/2

Step-by-step explanation:

7x-2y=11

Subtract 7x from each side

7x-2y -7x = -7x+11

-2y = -7x+11

Divide each side by -2

-2y/-2 = -7x/-2 +11/-2

y = 7/2x -11/2

8 0
3 years ago
Read 2 more answers
The formula for a trapezoid relates the area A, the two bases, a and b, and the height, h. A=(a+b)/2 h Solve for a.
yKpoI14uk [10]

Answer:

a=\frac{2A}{h}-b

Step-by-step explanation:

Hello, I think I can help you with this.

According to the information provided in the problem, the area of ​​a trapezoid is given by

A=\frac{a+b}{2} *h\\

Step 1

solve for a, it means isolate a

A=\frac{a+b}{2} *h\\divide\ both\ sides\ by\ h\\\\\frac{A}{h}= \frac{\frac{a+b}{2} *h}{h} \\\frac{A}{h}=\frac{a+b}{2}\\\\Now, multiply\ both\ sides\ by\ two\\\\ 2*\frac{A}{h}=2*\frac{a+b}{2}\\2*\frac{A}{h}=a+b\\\frac{2A}{h}=a+b\\\\subtract\ b\ for\ both\ sides\\\frac{2A}{h}-b=a+b-b\\a=\frac{2A}{h}-b

Have a good day.

5 0
3 years ago
True or False <br> If an acute angle is 80o then we add the obtuse angle of 110o to equal 180o?
DIA [1.3K]

Answer:

true

Step-by-step explanation:

5 0
2 years ago
What is (64 p to the power of 18)to the power of 5/6?
murzikaleks [220]
Im not understanding what you are asking
3 0
3 years ago
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