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Naily [24]
2 years ago
10

For Valentine's Day last year Sonia's flower shop delivered 68 flower arrangements. This year they delivered 95. How many more f

lower arrangements did they deliver this year than last year?
Mathematics
1 answer:
Vlada [557]2 years ago
3 0
Answer: 27


Explanation: 95-68
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4c
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3 years ago
PLEASE HELP I think is A or D
Natalka [10]
Looking at the angles of the triangles

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3 years ago
The area of a rectangle is 42 square feet.
Alchen [17]

Answer:

26 ft and 46 ft.

Step-by-step explanation:

The prime  factors of 42 are 2 * 3 * 7.

Possible lengths and widths  are:

L = 7, W = 6 giving a perimeter of  2*7 + 2*6 = 26 ft.

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L = 21, W = 2 giving perimeter = 46 ft.

3 0
2 years ago
Does anybody know how to do time with exponential decay
My name is Ann [436]
<span>From the message you sent me:

when you breathe normally, about 12 % of the air of your lungs is replaced with each breath. how much of the original 500 ml remains after 50 breaths

If you think of number of breaths that you take as a time measurement, you can model the amount of air from the first breath you take left in your lungs with the recursive function

b_n=0.12\times b_{n-1}

Why does this work? Initially, you start with 500 mL of air that you breathe in, so b_1=500\text{ mL}. After the second breath, you have 12% of the original air left in your lungs, or b_2=0.12\timesb_1=0.12\times500=60\text{ mL}. After the third breath, you have b_3=0.12\timesb_2=0.12\times60=7.2\text{ mL}, and so on.

You can find the amount of original air left in your lungs after n breaths by solving for b_n explicitly. This isn't too hard:

b_n=0.12b_{n-1}=0.12(0.12b_{n-2})=0.12^2b_{n-2}=0.12(0.12b_{n-3})=0.12^3b_{n-3}=\cdots

and so on. The pattern is such that you arrive at

b_n=0.12^{n-1}b_1

and so the amount of air remaining after 50 breaths is

b_{50}=0.12^{50-1}b_1=0.12^{49}\times500\approx3.7918\times10^{-43}

which is a very small number close to zero.</span>
5 0
3 years ago
Please help me please will give brainliest to anyone <br><br><br><br><br>only do number 11​
AnnZ [28]

9514 1404 393

Answer:

  9.  ±1, ±2, ±3, ±6

  11.  ±1, ±2, ±3, ±4, ±6, ±12

Step-by-step explanation:

The possible rational roots are (plus or minus) the divisors of the constant term, divided by the divisors of the leading coefficient.

Here, the leading coefficient is 1 in each case, so the possible rational roots are plus or minus a divisor of the constant term.

__

9. The constant is -6. Divisors of 6 are 1, 2, 3, 6. The possible rational roots are ...

  ±{1, 2, 3, 6}

__

11. The constant is 12. Divisors of 12 are 1, 2, 3, 4, 6, 12. The possible rational roots are ...

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_____

A graphing calculator is useful for seeing if any of these values actually are roots of the equation. (The 4th-degree equation will have 2 complex roots.)

8 0
3 years ago
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