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jok3333 [9.3K]
3 years ago
8

If a = m 2 + 2, what is the value of a when m = -3?

Mathematics
1 answer:
Fed [463]3 years ago
4 0
A = (-3)2 +2 = -4
answer is -4

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20 is what percent of 25 ?
Musya8 [376]

Answer: 80%

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Help help help help help
aleksklad [387]

Answer:

<h2><u>Toothpaste</u></h2>

Smiles = $0.215 per ounce

Tartar Free = $0.2075 per ounce

Bright = $0.19875 per ounce

I will buy Bright because it is the cheapest.

<h2><u>Sunscreen Lotion</u></h2>

Bronze Smart = $0.23625 per ounce

Ray Block = $0.25 per ounce

Healthy Glow = $0.3725 per ounce

I will buy Bronze Smart because it is the cheapest sunscreen here.

<h2><u>Deodorant</u></h2>

Fresh = $0.29875 per ounce

Clean Scent = $0.259 per ounce

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I will buy Spring because it costs less than the other deodorants.

Step-by-step explanation:

divide the cost by the ounces and you will get the cost per ounce

Have a nice day! :-)

3 0
3 years ago
I) 54,2 X 94= ?
CaHeK987 [17]

Answer:

I) 54.2 X 94 = 5094.8

J) 36.39 X 28 = 1018.92

K) 43.73 X 74.4 = 3253.512

5 0
3 years ago
Read 2 more answers
How do you solve this equation?
Travka [436]
Exponentail thingies

easy, look at all them them, see that they have 5 in common?
rremember how esay it was to factor
ax^2+bx+c=0

now we have
5^(2x)-6(5^x)+5=0
remember that 5^(2x)=(5^2)^x or (5^x)^2
in other words, we can rewrite it as
1(5^x)^2-6(5^x)+5=0
if yo want, replace 5^x with a and factor
1a^2-6a+5=0
(a-1)(a-5)=0
a=5^x
(5^x-1)(5^x-5)=0
set each to zero

5^x-1=0
5^x=1
take the log₅ of both sides
x=log₅1


5^x-4=0
5^x=4
take the log₅ of both sides
x=log₅4

x=log₅1 and/or log₅4







second quesiton

same thing

1(2^x)-10(2^x)+16=0
factor
(2^x-8)(2^x-2)=0
set each to zero

2^x-8=9
2^x=8
x=3

2^x-2=0
2^x=2
x=1

x=3 or 1







first one
x=log₅1 and/or log₅4
second one
x=1 and/or 3


7 0
3 years ago
Q and R are not mutually exclusive events. p (q) = 3/5 p(r) = 1/3 and p ( q and r)= 1/5 find P(Q or R).
V125BC [204]
Recall the inclusion/exclusion principle:

\mathbb P(Q\cup R)=\mathbb P(Q)+\mathbb P(R)-\mathbb P(Q\cap R)

which means

\mathbb P(Q\text{ or }R)=\dfrac35+\dfrac13-\dfrac15=\dfrac{11}{15}
5 0
3 years ago
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