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LuckyWell [14K]
3 years ago
7

Samuel already has 56 flowers in his garden, and he can also grow 1 flower with every seed packet he uses. How many seed packets

does Samuel need to have a total of 62 flowers in his garden?​
Mathematics
1 answer:
AveGali [126]3 years ago
5 0

Answer:

6

Step-by-step explanation:

he will need that many because if you subtract 56 from 62 you will get 6 and you need one packet per flower so.. yea. 6

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Make a the subject of the formula<br> V= u+ at
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V=u + at
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6 0
2 years ago
The probability that a civil servant own a car is 1/6,if two civil servants are selected at random.find the probability that
Elodia [21]

Answer:

The data we have is:

the probability that a civil servant own a car is 1/6

Two civil servants are selected at random.

a) The probability that each own a car.

Ok, here we have two events:

Person 1 haves a car.

Person 2 haves a car.

The probability of each of those events is the same, 1/6.

P1 = 1/6

P2 = 1/6

Now, the probability of both events happening at the same time is equal to the product of the individual probabilities.

P = P1*P2 = (1/6)*(1/6) = 1/36.

b) Only one has a car.

Suppose that Person 1 has the car and Person 2 has not a car.

The probability for person 1 is 1/6.

And for person 2, is the negation of having a car:

So if we have prob of having a car = 1/6

Then the probability of not having a car is = 1 - 1/6 = 5/6.

Then we have:

P1 = 1/6

P2 = 5/6.

The joint probability is:

P = P1*P2 = (1/6)*(5/6) = 5/36.

But we also have the case where person 1 does not have a car, and person 2 does have one, then we have a permutation, and the actual probability is two times the obtained above.

P = 2*(5/36) = 10/36

4 0
3 years ago
Find the value of x and the length of both chords if BW=2x+10, WD=4, CW=7x+5, and WE=2.
daser333 [38]

Answer:

The value of x is 5

The lengths of the chords are 24 units and 42 units

Step-by-step explanation:

In a circle if two chords intersected at a point inside it there are four segments created, two in each cord, the products of the lengths of the line segments on each chord are equal

∵ BD and CE are two chords in a circle intersected at W

∴ The two segments of chord BD are BW and WD

∴ The two segments of chord CE are CW and WE

- By using the rule above

∴ BW × WD = CW × WE

∵ BW = 2x + 10 and WD = 4

∵ CW = 7x + 5 and WE = 2

- Substitute them in the rule above

∴ (2x + 10) × 4 = (7x + 5) × 2

∴ 4(2x) + 4(10) = 2(7x) + 2(5)

∴ 8x + 40 = 14x + 10

- Subtract 14x from both sides

∴ - 6x + 40 = 10

- Subtract 40 from both sides

∴ - 6x = - 30

- Divide both sides by - 6

∴ x = 5

∵ Chord BD = 2x + 10 + 4

∴ Chord BD = 2x + 14

- Substitute the value of x to find its length

∴ Chord BD = 2(5) + 14 = 10 + 14

∴ Chord BD = 24 units

∵ Chord CE = 7x + 5 + 2

∴ Chord CE = 7x + 7

- Substitute the value of x to find its length

∴ Chord CE = 7(5) + 7 = 35 + 7

∴ Chord CE = 42 units

5 0
3 years ago
Abby earned $56 in 7 hours at her job today. She wants to know how much she could earn tomorrow if she works 34 hours at the sam
frez [133]

Answer:

It will be $85,  34÷ 4

will give you 8.5 then you multiply it by 10,× 10=85

5 0
3 years ago
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Elden [556K]

2x+3(6)=36

2x+36-18

x=18/2

9 is your answer

3 0
3 years ago
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