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egoroff_w [7]
3 years ago
7

Can someone help me with this problem plz

Mathematics
2 answers:
myrzilka [38]3 years ago
8 0
5/3+35
5+105 over 3
x= 36 2/3
Nutka1998 [239]3 years ago
6 0
The answer is: 110/3 = 36 ⅔ ; or, write as: 110/3 ; or, write as 36.66666667;
__________________________
Explanation: (Two methods):
_____________________________________________
Method 1):
____________
Since: "(1/3)x" and "7x" are "like terms" , add them together, to get:
____________________________________________________
"(7 + 1/3)x "
________________
→ 7 = 7/1 = ?/3 ; → (7*3)/ (1*3) = 21/3;  
→ 7 = 21/3 ; 

→ 7  1/3 = 7 + 1/3 = 21/3 + 1/3 = 22/3; 

→ (7 1/3)x  = (22/3) x

→ We have: "(22/3)x" ;  x = 5 ;

→  So substitute the "5" for "x"; and solve the expression:
→  (22/3)x = (22/3)*5 = (22*5) / (3*1) = 110/3 = 36 ⅔
____________
Method 2):
________________________________________
Either: 1):
__________________________________
 Given:  (1/3)x + 7x ;  x = 5; Solve for "x" .
_____________________________________________
    → Substitute the given value, "5", for "x"; to solve the expression:
____________________________
    →  (1/3)*5  +  7* 5  = (5/3)  + 35 = 1 ⅔ + 35 = 36 ⅔ ; or write as "110/3"; or, write as: 36.66667.
___________________
Or:  2):  
_____________________________________
 Given:  (1/3)x + 7x ;  x = 5; Solve for "x" .
_____________________________________________
    → Substitute the given value, "5", for "x"; to solve the expression:
Given:  (1/3)x + 7x ;  x = 5; Solve for "x" .
    →{Note: Similar to, a bit different from, the above method):
_____________________________________________
  →Here is what is done differently:
    → (1/3)x + 7x → = (x/3) + 7x) ;
_______________________________
Now, we have: 
_______________________________
→ (x/3) + 7x ; x = 5; → Plug in the value, "5" for the "x" values:
_______________________________
→ (5/3) + (7*5) = (5/3) + 35 = 1 ⅔ + 35 = 36 ⅔ ; or write as "110/3"; or, write as: 36.66667.
_________________________________
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Isabelle bought some stationery. 1/3 of them were pencils. 5/8 of the remainder were erasers and the rest were rulers. The cost
kobusy [5.1K]

Answer:

Isabelle spent $52.50 more on Erasers than rulers.

Step-by-step explanation:

Step 1

Find the quantity of each stationery bought in fraction

Let us represent the total fraction of what Isabelle bought as: x

1/3x = quantity of pencils bought

5/8 of the remainder = quantity of erasers bought

The remainder = x - 1/3x = 2/3x

5/8 of 2/3x = 5/8 × 2/3x = 5/12x

Hence, 5/12x = quantity of erasers bought

The rest is rulers

1 - (1/3 + 5/12)

1 - (4 + 5/12)

1 - 9/12

1 - 3/4

= 1/4x

Hence, 1/4 = quantity of rulers bought.

Step 2

We find the number of stationeries that Isabelle bought.

The cost of the stationery is

a Pencil: $1.20

an eraser: $1

a ruler: $0.50.

Total amount spent on stationery = 169.50

We have this equation

1.20 × 1/3x + 1 × 5/12x + 0.50 × 1/4x = 169.50

0.4x + 0.4166666667x + 0.125x =

169.50

0.9416666667x = 169.50

x = 169.50 /0.9416666667

x = 179.99999999

Approximately , the number of stationeries that Isabelle bought = x = 180

Step 3

Find the number and the amount spent on each stationery that Isabelle bought

a) i) Quantity of pencils bought = 1/3 x

x = 180

= 1/3 × 180

= 60 pencils

ii) Amount spent on pencils

If 1 pencil = $1.20

60 pencils =

60 × 1.20 = $72

b) i) Quantity of Erasers bought = 5/12x

x = 180

= 5/12 × 180

= 75 pencils

ii) Amount spent on Eraser

If 1 pencil = $1

75 pencils =

75 × 1 = $75

c) i) Quantity of rulers bought = 1/4 x

x = 180

= 1/4 × 180

= 45 pencils

ii) Amount spent on pencils

If 1 pencil = $0.50

45 pencils =

45 × 0.50 = $22.50

Step 4

We were asked to calculate how much more did she spend on erasers than rulers.

In step 3, the amount spent on Erasers = $75

the amount spent on ruler = $22.5

The difference in the amount spent = $75 - $22.5

= $52.5

Therefore, Isabelle spent $52.50 more on Erasers than rulers.

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