The answer is: 110/3 = 36 ⅔ ; or, write as: 110/3 ; or, write as 36.66666667; __________________________ Explanation: (Two methods): _____________________________________________ Method 1): ____________ Since: "(1/3)x" and "7x" are "like terms" , add them together, to get: ____________________________________________________ "(7 + 1/3)x " ________________ → 7 = 7/1 = ?/3 ; → (7*3)/ (1*3) = 21/3; → 7 = 21/3 ;
→ 7 1/3 = 7 + 1/3 = 21/3 + 1/3 = 22/3;
→ (7 1/3)x = (22/3) x
→ We have: "(22/3)x" ; x = 5 ;
→ So substitute the "5" for "x"; and solve the expression: → (22/3)x = (22/3)*5 = (22*5) / (3*1) = 110/3 = 36 ⅔ ____________ Method 2): ________________________________________ Either: 1): __________________________________ Given: (1/3)x + 7x ; x = 5; Solve for "x" . _____________________________________________ → Substitute the given value, "5", for "x"; to solve the expression: ____________________________ → (1/3)*5 + 7* 5 = (5/3) + 35 = 1 ⅔ + 35 = 36 ⅔ ; or write as "110/3"; or, write as: 36.66667. ___________________ Or: 2): _____________________________________ Given: (1/3)x + 7x ; x = 5; Solve for "x" . _____________________________________________ → Substitute the given value, "5", for "x"; to solve the expression: Given: (1/3)x + 7x ; x = 5; Solve for "x" . →{Note: Similar to, a bit different from, the above method): _____________________________________________ →Here is what is done differently: → (1/3)x + 7x → = (x/3) + 7x) ; _______________________________ Now, we have: _______________________________ → (x/3) + 7x ; x = 5; → Plug in the value, "5" for the "x" values: _______________________________ → (5/3) + (7*5) = (5/3) + 35 = 1 ⅔ + 35 = 36 ⅔ ; or write as "110/3"; or, write as: 36.66667. _________________________________
