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Vanyuwa [196]
2 years ago
11

The graph of a rational function has local maximum at (-1,0) and (8,0). The complex number 2+3i is a zero of the function. What

is the least possible degree of the function?

Mathematics
1 answer:
Natali5045456 [20]2 years ago
5 0

Answer:

what grade are you?....

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PLZ HELPPP<br />
Alexeev081 [22]
V=vanila
c=chocolate

4v+1c=45
v+c=27

mulitply 2nd equation by -1 and add to top one

-v-c=-27
<u>4v+1c=45 +</u>
<u />3v+0c=18

3v=18
divide by 3
v=6

sub back
v+c=27
6+c=27
c=21

21 choc and 6 van





A.
v+c=27
4v+1c=45
v=number of vanila wafers bought
c=number of chocolate wafers bought

B. 21 chocolate and 7
I got the answer with math because math is fun and tada
6 0
3 years ago
What is the radius of
Ulleksa [173]

Answer:

143.2 yards

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Find the general solution of the differential equation. (Use C for any needed constant.) dy dx = 1 − y
daser333 [38]

Answer:

Step-by-step explanation:

Give the DE

dy/dx = 1-y

Using variable separable method

dy = (1-y)dx

dx = dy/(1-y)

Integrate both sides

 ∫dx =  ∫dy/(1-y)

 ∫dy/(1-y)=  ∫dx

-ln(1-y) = x+C

ln(1-y)^-1 = x+C

Apply e to both sides

e^ln(1-y)^-1 = e^,(x+C)

(1-y)^-1 = Ce^x

1/(1-y) = Ce^x

4 0
4 years ago
The line that contains the point Q( 1, -2) and is parallel to the line whose equation is
Triss [41]
Let's call this line y=mx+C, whereby 'm' will be its gradient and 'C' will be its constant.

If this line is parallel to the line you've just mentioned, it will have a gradient 2/3. We know this, because when we re-arrange the equation you've given us, we get...

y-4=\frac { 2 }{ 3 } \left( x-3 \right) \\ \\ y-4=\frac { 2 }{ 3 } x-2\\ \\ y=\frac { 2 }{ 3 } x-2+4\\ \\ y=\frac { 2 }{ 3 } x+2

So, at the moment, our parallel line looks like this...

y=(2/3)*x + C

However, you mentioned that this line passes through the point Q(1, -2). If this is the case, for the line (almost complete) above, when x=1, y=-2. With this information, we can figure out the constant of the line we want to find.

-2=(2/3)*(1) + C

Therefore:

C = - 2 - (2/3)

C = - 6/3 - 2/3

C = - 8/3

This means that the line you are looking for is:

y=(2/3)*x - (8/3)

Let's find out if this is truly the case with a handy graphing app... Well, it turns out that I'm correct.

3 0
3 years ago
SAQ 5.1
iVinArrow [24]

Answer:

1. (i) 7, 21, 63, 189

(ii) 20, 10, 5, 2.5

2. (i) n²+n (where n = 1, 2, 3, ..)

(ii) 8/(10^n) (where n = 1, 2, 3, ..)

(iii) 1/(n+1) (where n = 1, 2, 3, ..)

4 0
3 years ago
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