V=vanila
c=chocolate
4v+1c=45
v+c=27
mulitply 2nd equation by -1 and add to top one
-v-c=-27
<u>4v+1c=45 +</u>
<u />3v+0c=18
3v=18
divide by 3
v=6
sub back
v+c=27
6+c=27
c=21
21 choc and 6 van
A.
v+c=27
4v+1c=45
v=number of vanila wafers bought
c=number of chocolate wafers bought
B. 21 chocolate and 7
I got the answer with math because math is fun and tada
Answer:
143.2 yards
Step-by-step explanation:
Answer:
Step-by-step explanation:
Give the DE
dy/dx = 1-y
Using variable separable method
dy = (1-y)dx
dx = dy/(1-y)
Integrate both sides
∫dx = ∫dy/(1-y)
∫dy/(1-y)= ∫dx
-ln(1-y) = x+C
ln(1-y)^-1 = x+C
Apply e to both sides
e^ln(1-y)^-1 = e^,(x+C)
(1-y)^-1 = Ce^x
1/(1-y) = Ce^x
Let's call this line y=mx+C, whereby 'm' will be its gradient and 'C' will be its constant.
If this line is parallel to the line you've just mentioned, it will have a gradient 2/3. We know this, because when we re-arrange the equation you've given us, we get...

So, at the moment, our parallel line looks like this...
y=(2/3)*x + C
However, you mentioned that this line passes through the point Q(1, -2). If this is the case, for the line (almost complete) above, when x=1, y=-2. With this information, we can figure out the constant of the line we want to find.
-2=(2/3)*(1) + C
Therefore:
C = - 2 - (2/3)
C = - 6/3 - 2/3
C = - 8/3
This means that the line you are looking for is:
y=(2/3)*x - (8/3)
Let's find out if this is truly the case with a handy graphing app... Well, it turns out that I'm correct.
Answer:
1. (i) 7, 21, 63, 189
(ii) 20, 10, 5, 2.5
2. (i) n²+n (where n = 1, 2, 3, ..)
(ii) 8/(10^n) (where n = 1, 2, 3, ..)
(iii) 1/(n+1) (where n = 1, 2, 3, ..)