When a document repository is down when you attempt to access it, the ISA principle Authentication is being violated. The authentication method is done during the log on phase and is performed by the ISA server which requests certificate. <span>The client then needs to send the appropriate client certificate to the server in order to be authenticated and to have access to the document.</span>
Because it is a very fun game and if it is fun people like it
Answer:
- common = []
- num1 = 8
- num2 = 24
- for i in range(1, num1 + 1):
- if(num1 % i == 0 and num2 % i == 0):
- common.append(i)
- print(common)
Explanation:
The solution is written in Python 3.
Firstly create a common list to hold a list of the common factor between 8 and 24 (Line 1).
Create two variables num1, and num2 and set 8 and 24 as their values, respectively (Line 3 - 4).
Create a for loop to traverse through the number from 1 to 8 and use modulus operator to check if num1 and num2 are divisible by current i value. If so the remainder of both num1%i and num2%i will be zero and the if block will run to append the current i value to common list (Line 6-8).
After the loop, print the common list and we shall get [1, 2, 4, 8]
Explanation:
This is easily solvable with a for loop. Something like:
(I assume c++)
#include <iostream>
#include <string>
int main() {
take_input: //tag
std::string input;
cin >> input; //take the input
int spaceCount = 0;
char checking;
for(unsigned int i = 0; i == input.length(); ++i) {
checking = spaceCount[i];
if(checking == ' ')
spaceCount++;
}
if(spaceCount >= 1 && input.length >= 5)
std::cout << "Your name is " + input;
else
goto take_input; // reasks for input if the conditions are not met
return 0;
};
**remove all spaces before using the code, the if statements are messed up
