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3 years ago

Could I please have some help

Mathematics

1 answer:

goldenfox [79]3 years ago

3 0

I think it’s D .but I’m not sure

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Janette has 386 pennies. 58 nickels and 19 dimes If Janette exchanges her coins for dollars, how many dollars will she have? Ho

svet-max [94.6K]

Answer:

$8 ; 66 cents

Step-by-step explanation:

Given that:

Worth of penny, dimes and Nickel in cents and dollars

Nickel, n = 5 cents = $0.05

Dimes, d = 10 cent = $0.1

Penny, p = 1 cent = $0.01

Multiplying the number of each coin with its respective value ;

386(0.01) + 58(0.05) + 19(0.1)

$3.86 + $2.9 + $1.9

= $8.66

Changing it to dollar ,

$8.66 dollars = 8 dollars ;

$0.66 = 66 cents

6 0

3 years ago

Suppose you produce a camera that costs $50 to make. At a selling price of $45, you will _____.

Daniel [21]

You will lose money. Because $50 to make subtract $45 to sell (50-45) leaves you losing $5.

4 0

4 years ago

Read 2 more answers

Jasmine bought 32 kiwi fruit for $16. IfJasmine has $4, how many kiwi can shebuy?

Sav [38]

Answer:

8 kiwis

Step-by-step explanation:

(÷4)32=$16(÷4)

8 =$4

hope this helps

7 0

3 years ago

The radius of a spherical balloon is measured as 20 inches, with a possible error of 0.03 inch. Use differentials to approximate

soldi70 [24.7K]

Answer:

a) $V = 33510.322\,in^{3}$ , b) $A_{s} = 5026.548\,in^{2}$ , c) $\% V = 0.450\,\%$ , $\%A_{s} = 0.300\,\%$ .

Step-by-step explanation:

The volume and the surface area of the sphere are, respectively:

$V = \frac{4}{3}\pi \cdot r^{3}$

$A_{s} = 4\pi \cdot r^{2}$

a) The volume of the sphere is:

$V = \frac{4}{3}\pi \cdot (20\,in)^{3}$

$V = 33510.322\,in^{3}$

b) The surface area of the sphere is:

$A_{s} = 4\pi \cdot (20\,in)^{2}$

$A_{s} = 5026.548\,in^{2}$

c) The total differentials for volume and surface area of the sphere are, respectively:

$\Delta V = 4\pi\cdot r^{2}\,\Delta r$

$\Delta V = 4\pi \cdot (20\,in)^{2}\cdot (0.03\,in)$

$\Delta V = 150.796\,in^{3}$

$\Delta A_{s} = 8\pi\cdot r \,\Delta r$

$\Delta A_{s} = 8\pi \cdot (20\,in)\cdot (0.03\,in)$

$\Delta A_{s} = 15.080\,in^{2}$

Relative errors are presented hereafter:

$\%V = \frac{\Delta V}{V}\times 100\%$

$\%V = \frac{150.796 \,in^{3}}{33510.322\,in^{3}}\times 100\,\%$

$\% V = 0.450\,\%$

$\% A_{s} = \frac{\Delta A_{s}}{A_{s}}\times 100\,\%$

$\% A_{s} = \frac{15.080\,in^{2}}{5026.548\,in^{2}}\times 100\,\%$

$\%A_{s} = 0.300\,\%$

4 0

3 years ago

PLEASE HELP

Serga [27]

180=9×w
length=9
width=20
perimeter=58

5 0

3 years ago

Could I please have some help​

Could I please have some help