1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Phoenix [80]
2 years ago
12

Please help fast !!!! I really Don't understad This i need help please its so frustrating

Mathematics
1 answer:
jeka942 years ago
4 0
Whit what you need help?
You might be interested in
Solve: 3y+5=-1 . What’s the solution?
Harman [31]

Answer:

hmmm

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Please help and answer the table
anastassius [24]
The table on the left is going up by 9, and the other side is going up by 4. So in 12 hours you made 27.. sorry if that is bad
6 0
3 years ago
Read 2 more answers
The Carousel at Carowinds has 4 rings of horses. Fred is riding on the inner ring, which has a radius of 7 feet. Juan is riding
nikdorinn [45]

Answer:

Juan travel 31.4 feet farther than Fred in one rotation.

Step-by-step explanation:

In this problem we need to determine the change in linear position of Fred and Juan, whose formula is:

s=\theta \cdot r (Eq. 1)

Where:

r - Radius, measured in feet.

\theta - Angular arch, measured in radians.

s - Change in linear position, measured in feet.

If both makes one rotation in the carousel, we obtain the change in linear position of each player:

Fred (r = 7\,ft, \theta = 2\pi)

s= 2\pi\cdot (7\,ft)

s = (3.14)\cdot (7\,ft)

s = 21.98\,ft

Juan (r = 17\,ft, \theta = 2\pi)

s= 2\pi\cdot (17\,ft)

s = (3.14)\cdot (17\,ft)

s = 53.38\,ft

And the difference between both travelled distances is:

\Delta s = 53.38\,ft-21.98\,ft

\Delta s = 31.4\,ft

Juan travel 31.4 feet farther than Fred in one rotation.

4 0
3 years ago
I’m having trouble with this question. if anyone can answer it would mean a lot
natulia [17]

Answer:

Step-by-step explanation:

x = - 48/-8  = 6

c = c^2/c^1 = c^(2-1) = c^1

d = d^4 / d^1 = d^(4 - 1) = d ^3

x = 6

e = 1

f = 3

4 0
3 years ago
A computer program in Shannon’s computer carries out a single mathematical operation in 1.5 × 10-6 seconds. How much time would
kykrilka [37]

1/1.5 * 10^-6 = 2500/x

x = 1.5 * 10^-6 * 2500

x = 0.00375 or 3.75 * 10^-3 second.

3 0
3 years ago
Other questions:
  • Four times a number is the same as the difference of three times a number and four find the number round your answer to the near
    8·2 answers
  • All parbolas with vertical directrix open to the left or right<br> True or false
    5·1 answer
  • Jim is M years old. His daughter is 21 years yonger than him. How old is Jim's daughter. Express your answer in terms of M.
    9·2 answers
  • What is the answer to 32.6 - n = 10.2
    12·1 answer
  • You need to buy tissue paper sheets to cushion gifts being placed inside a box. The box is 12 inches wide by 16 inches long. The
    11·1 answer
  • E fence factorise completely<br>this expression<br>144​
    13·1 answer
  • What’s the digit you need to input in the space with the question mark to complete the code for the safe? Here’s a hint to save
    15·2 answers
  • What is the solution to the system of equations below?<br> 4x - 2y = -4<br> 8x - 4y = 4
    13·1 answer
  • So I tried everything I could but I still don’t know
    11·1 answer
  • What is the missing length?<br> с<br> 4 mm<br> 3 mm<br> 2<br> area = 10 mm
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!