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3 years ago

This may vary in your state, but S/P2 recommends keeping all environmental documentation a minimum of:

Computers and Technology

2 answers:

Anettt [7]3 years ago

4 0

A would be the answer!!!...

Kazeer [188]3 years ago

4 0

Answer:

C) 3 years

Explanation:

Documentation

Both OSHA and the EPA require shops to provide and keep specific documentation. Missing or improper documentation is a major cause of OSHA and EPA violations. Make it a policy to document all compliance-related actions—and keep your files up-to-date. Make sure files are accurately labeled and easy to find. During an EPA or OSHA inspection, the inspector will ask to see your files. Even if you handle and dispose of waste properly, you will still be subject to fines and penalties if you are unable to provide supporting documentation.

Always keep one copy of documentation on-site and a backup copy off-site.

Keep all compliance documentation for a minimum of three years—or longer, if required in your area. Laws can vary by state as to the length of time you must keep the paperwork. If a violation ever occurs, or the organization is sold, the business will benefit from a complete hazardous waste file.

For more details, visit CFR Title 40: Protection of Environment.

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Given that String[] str has been initialized, to get a copy of str[0] with all characters converted to upper case, use the follo

Strike441 [17]

Answer: str[0].toUpperCase();

Explanation:

str[0] is pointing to the first character of the entire string and the code str[0].toUpperCase() will convert the characters to upper case if they are in lowercase and will remain unchanged if they are already in upper case.

7 0

3 years ago

Add three methods to the Student class that compare twoStudent objects. One method (__eq__) should test for equality. A second m

shusha [124]

Answer:

class Student(object):

def __init__(self, name, number):

self.name = name

self.scores = []

for count in range(number):

self.scores.append(0)

def getName(self):

return self.name

def setScore(self, i, score):

self.scores[i - 1] = score

def getScore(self, i):

return self.scores[i - 1]

def getAverage(self):

return sum(self.scores) / len(self._scores)

def getHighScore(self):

return max(self.scores)

def __eq__(self,student):

return self.name == student.name

def __ge__(self,student):

return self.name == student.name or self.name>student.name

def __lt__(self,student):

return self.name<student.name

def __str__(self):

return "Name: " + self.name + "\nScores: " + \

" ".join(map(str, self.scores))

def main():

student = Student("Ken", 5)

print(student)

for i in range(1, 6):

student.setScore(i, 100)

print(student)

print("\nSecond student")

student2 = Student("Ken", 5)

print(student2)

print("\nThird student")

student3 = Student("Amit", 5)

print(student3)

print("\nChecking equal student1 and student 2")

print(student.__eq__(student2))

print("\nChecking equal student1 and student 3")

print(student.__eq__(student3))

print("\nChecking greater than equal student1 and student 3")

print(student.__ge__(student3))

print("\nChecking less than student1 and student 3")

print(student.__lt__(student3))

if __name__ == "__main__":

5 0

3 years ago

A clock is reading 10:27:54.0 (hr:min:sec) when it is discovered to be 4 seconds fast. Explain why it is undesirable to set it b

lara31 [8.8K]

Answer:

(a)Applications Time Stamp Events

(b)S=0.5(W- $T_{skew}$ )+ $T_{skew}$ , where $T_{skew}$ ≤W≤ $T_{skew}$ +8.

Explanation:

Some applications assume that clocks always advance, so they could timestamp events under this assumption.

In our case we have the wrong timed clock, say W and the hardware clock H which is supposed to advance at a perfect rate.

We proceed to construct a software clock such that after 8 seconds we can replace the wrong timed clock with the software clock in good conditions.

Let us denote the software clock with S.

Then, S=c(W- $T_{skew}$ )+ $T_{skew}$ where:

$T_{skew}$ =The current Time(10:27:54) and;

c is to be found.

We already know that S= $T_{skew}$ +4 when W= $T_{skew}$ +8,

So:

S=c(W- $T_{skew}$ )+ $T_{skew}$

$T_{skew}$ +4=c( $T_{skew}$ +8- $T_{skew}$ )+ $T_{skew}$

4=8c

c=0.5

We obtain the formula

S=0.5(W- $T_{skew}$ )+ $T_{skew}$ , where $T_{skew}$ ≤W≤ $T_{skew}$ +8.

4 0

3 years ago

A network interface port has collision detection and carrier sensing enabled on a shared twisted-pair network. From this stateme

hram777 [196]

Answer:

This is an Ethernet port operating at half duplex.

Explanation:

Modern Ethernet networks built with switches and full-duplex connections no longer utilize CSMA/CD. CSMA/CD is only used in obsolete shared media Ethernet (which uses repeater or hub).

7 0

3 years ago

Read 2 more answers

Which is better computer science or software engineering?

mina [271]

you have to be extremely talented to be a software engineer so I see that as way more complex and cool.

3 0

4 years ago

Read 2 more answers