un diagrama de flujo donde se gana una partida de ajedrez teniendo en cuenta los movimientos de la otra persona
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Using the knowledge of computational language in C++ it is possible to write a code that given an array of integers a, your task is to count the number of pairs i and j.
<h3>Writting the code:</h3><em>// C++ program for the above approach</em>
<em> </em>
<em>#include <bits/stdc++.h></em>
<em>using namespace std;</em>
<em> </em>
<em>// Function to find the count required pairs</em>
<em>void getPairs(int arr[], int N, int K)</em>
<em>{</em>
<em> // Stores count of pairs</em>
<em> int count = 0;</em>
<em> </em>
<em> // Traverse the array</em>
<em> for (int i = 0; i < N; i++) {</em>
<em> </em>
<em> for (int j = i + 1; j < N; j++) {</em>
<em> </em>
<em> // Check if the condition</em>
<em> // is satisfied or not</em>
<em> if (arr[i] > K * arr[j])</em>
<em> count++;</em>
<em> }</em>
<em> }</em>
<em> cout << count;</em>
<em>}</em>
<em> </em>
<em>// Driver Code</em>
<em>int main()</em>
<em>{</em>
<em> int arr[] = { 5, 6, 2, 5 };</em>
<em> int N = sizeof(arr) / sizeof(arr[0]);</em>
<em> int K = 2;</em>
<em> </em>
<em> // Function Call</em>
<em> getPairs(arr, N, K);</em>
<em> </em>
<em> return 0;</em>
<em>}</em>
See more about C++ code at brainly.com/question/17544466
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