Answer:
Alan buys 12.05 ounces of sour patch kids candy in all.
Step-by-step explanation:
We are given that Alan buys 5.3 ounces of sour patch kids candy. After sharing with his friends he returns to buy an additional 6.75 ounces.
And we have to find the total ounces he buys in all.
As we know that for finding the total quantity or amount, we will use addition for calculating it.
Firstly, Alan buys = 5.3 ounces of sour patch kids candy
Additional ounces of sour patch kids candy Alan buys = 6.75
So, the total ounces of sour patch kids candy he buys in all = 5.3 + 6.75
= 12.05 ounces
Hence, he buys 12.05 ounces in all.
Answer:
![15 \sqrt[3]{2}](https://tex.z-dn.net/?f=15%20%5Csqrt%5B3%5D%7B2%7D%20)
Step-by-step explanation:
![{(27 \times 250)}^{ \frac{1}{3} } = {(27 \times 125 \times 2)}^{ \frac{1}{3} } \\ = {27}^{ \frac{1}{3} } \times {125}^{ \frac{1}{3} } \times {2}^{ \frac{1}{3} } \\ = \sqrt[ 3]{27} \times \sqrt[3]{125} \times \sqrt[3]{2} \\ = \sqrt[3]{ {3}^{3} } \times \sqrt[3]{ {5}^{3} } \times \sqrt[3]{2} \\ = 3 \times 5 \times \sqrt[3]{2} \\ = 15 \sqrt[3]{2}](https://tex.z-dn.net/?f=%20%7B%2827%20%5Ctimes%20250%29%7D%5E%7B%20%5Cfrac%7B1%7D%7B3%7D%20%7D%20%20%3D%20%20%7B%2827%20%5Ctimes%20125%20%5Ctimes%202%29%7D%5E%7B%20%5Cfrac%7B1%7D%7B3%7D%20%7D%20%20%5C%5C%20%20%3D%20%20%7B27%7D%5E%7B%20%5Cfrac%7B1%7D%7B3%7D%20%7D%20%20%5Ctimes%20%20%7B125%7D%5E%7B%20%5Cfrac%7B1%7D%7B3%7D%20%7D%20%20%5Ctimes%20%20%7B2%7D%5E%7B%20%5Cfrac%7B1%7D%7B3%7D%20%7D%20%20%5C%5C%20%20%3D%20%20%5Csqrt%5B%203%5D%7B27%7D%20%20%5Ctimes%20%20%5Csqrt%5B3%5D%7B125%7D%20%20%5Ctimes%20%20%5Csqrt%5B3%5D%7B2%7D%20%20%5C%5C%20%20%3D%20%20%5Csqrt%5B3%5D%7B%20%7B3%7D%5E%7B3%7D%20%7D%20%20%5Ctimes%20%20%5Csqrt%5B3%5D%7B%20%7B5%7D%5E%7B3%7D%20%7D%20%20%5Ctimes%20%20%5Csqrt%5B3%5D%7B2%7D%20%20%5C%5C%20%20%3D%203%20%5Ctimes%205%20%5Ctimes%20%20%5Csqrt%5B3%5D%7B2%7D%20%20%5C%5C%20%20%3D%2015%20%5Csqrt%5B3%5D%7B2%7D%20)
B is the answer!
Explanation:
m^2 n^2 fits into both, you can take m^2 n^2 out of it both.
m is a common factor since you can take m out of both but it’s not the greatest common factor.
2n & 2m wouldn’t even be a common factor bc there is no 2n or 2m in neither.
Subtract 13.09 from 21.59 giving you 8.5. Since the amount of space on both the left and right margin have to be equal you would divide by 2 to get 4.25 on the left margin as well as the right.
