X = {3.898979486, -5.898979486}
x = {3.9 x -5.9}
Given:
A right angled triangle.
To find:
The value of x.
Solution:
We have,
Base = x
Hypotenuse = 
In a right angle triangle,

For the given triangle,


Multiply both sides by
.



Therefore, the required value of x is
.
Where are the inequalities?
Hello! You can answer this question by using the distributive property. Basically
a(b+c) = a(b) + a(c)
Let's apply it to this expression:
5x(x-4)
=5x(x)-5x(-4)