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3 years ago

A stack of one hundred twenty cards is placed next to a ruler, and the height of stack is measured to be

Mathematics

1 answer:

Aliun [14]3 years ago

6 0

If you do 34/120 you will get 0.283333333333333
Which is the thickness of one card

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HEEELLLPP PLEASEE I GIVE BRAINLIST!!!

Mila [183]

Take any of the valid pairs of points, use the formula
rate of change = (y2-y1)/(x2-x1)

Say we use P1=(0,21.4), P2=(3,19)
x1=0, y1=21.4
x2=3, y2=19

Rate of change = (21.4-19)/(0-3)=2.4/(-3) = -0.8 sq. ft/in of liquid

4 0

3 years ago

If the circumference of a circle is divided by the length of its diameter. whats the result

Mnenie [13.5K]

Answer:

3.14 or π (It's the same thing)

Step-by-step explanation:

If you divide the circumference by its diameter, the constant ratio is called Pi

8 0

3 years ago

The radius of a circular track is 50 feet. How many feet of fencing

mina [271]

314 feet of fencing

6 0

3 years ago

Suppose that a college determines the following distribution for X = number of courses taken by a full-time student this semeste

lidiya [134]

Answer:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 3*0.07 +4*0.4 +5*0.25 +6*0.28= 4.74$ In order to find the variance we need to calculate first the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 3^2*0.07 +4^2*0.4 +5^2*0.25 +6^2*0.28= 23.36$ And the variance is given by:

$Var(X) = E(X^2) +[E(X)]^2 = 23.36 -[4.74]^2 = 0.8924$

And the deviation would be:

$Sd(X) =\sqrt{0.8924} =0.9447$

Step-by-step explanation:

Previous concepts

The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.

The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).

Solution to the problem

For this case we have the following distribution given:

X 3 4 5 6

P(X) 0.07 0.4 0.25 0.28

We can calculate the mean with the following formula:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 3*0.07 +4*0.4 +5*0.25 +6*0.28= 4.74$

In order to find the variance we need to calculate first the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 3^2*0.07 +4^2*0.4 +5^2*0.25 +6^2*0.28= 23.36$

And the variance is given by:

$Var(X) = E(X^2) +[E(X)]^2 = 23.36 -[4.74]^2 = 0.8924$

And the deviation would be:

$Sd(X) =\sqrt{0.8924} =0.9447$

3 0

3 years ago

Can anyone help me with these 2 queen

Elan Coil [88]

Answer

1st is yes

2nd is no

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers